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Ne4ueva [31]
3 years ago
9

What is 12.165 in word from

Mathematics
1 answer:
Kamila [148]3 years ago
4 0
Twelve and one hundred sixty-five thousandths
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X/33=-2/3i don't know how to solve this some one help me please
Delvig [45]

Answer:

x/i=22

Step-by-step explanation:

x/33=2/3*i

*33       *33

x=2/3*33*i

/i              /i

x/i=2/3*33

x/i=22

6 0
3 years ago
Your car's back window is in the shape of a trapezoid with the dimensions shown. The 1616-inch window wiper cleans a part of the
ExtremeBDS [4]
<span>Semicircle area = circle area / 2 = (pi*r^2)/2 16 in is the radius. Let's call the area of this semicircle s. 3.14*16^2=s

</span><span>Trapezoid area = ((base 1 + base 2) / 2) * h Here, base 1 is 44 and base 2 is 36. The height (h) is 20. Let's call this trapezoid's area t. (44+36)/2 *20 = t
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<span>We can remove the area of the semicircle (that created by the windshield wiper) by subtracting it from the area of the trapezoid. t - s = uncleaned area [(44+36)/2 * 20] - [3.14 * 16^2] = uncleaned area</span>
5 0
3 years ago
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Answer this and i will give brainliest
seropon [69]

Answer:

2x = y

Step-by-step explanation:

As you can see in the table, y = 2x, this is proven by the fact that if you divide any value in the y of the table by 2 you will get its corresponding x value, proving that 2x = y is the function that is used to represent this table's value.

8 0
3 years ago
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How do I solve the equation in an interval from 0 to 2π ? 9 cos 2t = 6​
Ivahew [28]

9\cos(2t)=6\implies\cos(2t)=\dfrac23

Using the fact that cos is 2π-periodic, we have

\cos(2t)=\dfrac23\implies2t=\cos^{-1}\left(\dfrac23\right)+2n\pi

That is, \cos(\theta+2n\pi)=\cos\theta for any \theta and integer n.

\implies t=\dfrac12\cos^{-1}\left(\dfrac23\right)+n\pi

We get 2 solutions in the interval [0, 2π] for n=0 and n=1,

t=\dfrac12\cos^{-1}\left(\dfrac23\right)\text{ and }t=\dfrac12\cos^{-1}\left(\dfrac23\right)+\pi

4 0
3 years ago
5x88x9x7x3x9x10x31x47=
Gre4nikov [31]
1.09047708 E10 i guess
6 0
3 years ago
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