Given f (x) = 2×-2÷4, solve for f^1 (3)
1 answer:
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1995. 164 million
2001. 169 million
t = 2001 - 1995 = 6
169 =
![p^{6} = \frac{169}{164}= 1.0304878 \\ p = \sqrt[6]{1.0304878}](https://tex.z-dn.net/?f=%20p%5E%7B6%7D%20%3D%20%5Cfrac%7B169%7D%7B164%7D%3D%201.0304878%20%5C%5C%20%20p%20%3D%20%20%5Csqrt%5B6%5D%7B1.0304878%7D%20%20)
p = 1.00502
t 1 = 2015 - 2001 = 14
f ( t1 ) =
f (t1) = 169 * 1.0762 = 181.27
Answer: a country´s population in 2015 will be 181 million.
2001. 169 million
t = 2001 - 1995 = 6
169 =
p = 1.00502
t 1 = 2015 - 2001 = 14
f ( t1 ) =
f (t1) = 169 * 1.0762 = 181.27
Answer: a country´s population in 2015 will be 181 million.