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Semenov [28]
3 years ago
9

Which number would be an element of the set of integers but not an element of the set of whole numbers,0, -3, 5, -1/2?

Mathematics
1 answer:
iren [92.7K]3 years ago
8 0
Integers are negative or positive whole numbers
whole numbers do not include negatives

so ur answer is -3...it is considered an integer, but not a whole number
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Atraeus is solving the quadratic equation by completing the square.
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I think the value of a I think the answer is b
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The sun is behind a building and casting a shadow. How long is the shadow if the building is 25 feet tall and the angle, of the
Nana76 [90]
ANSWER

The length of the shadow is 49 ft to nearest feet.

EXPLANATION

We can find the length of the shadow using the tangent ratio.

Recall that,

\tan(27 \degree) = \frac{opposite}{adjacent}
From the diagram, the length of the shadow is the side of the triangle that is adjacent to the 27° angle

\tan(27 \degree) = \frac{45}{adjacent}

This implies that,

adjacent = \frac{45}{tan27 \degree}

adjacent = 49 .065

4 0
3 years ago
If someone runs 4 miles in 30 minutes how many will they run in 48 minutes
kakasveta [241]
First find out how fast they run 1 mile by dividing the time they ram ( 30 minutes) by the number of miles they ran (4)

30 minutes / 4 miles = 7.5 minutes per mile

now we know how fast they run divide the new overall time (48 minutes) by the speed (7.5 minutes) to find the number of miles they will run

48 / 7.5 = 6.4 miles
4 0
3 years ago
Solve the system. find x,y, and z please show all steps<br><br> x-y+z=1<br> x+y+3z=-3<br> 2x-y+2z=0
Mariulka [41]

Solving the system we get, x= -1, y= -2 and z= 0

Step-by-step explanation:

Solving the equations to find x, y and z

x-y+z=1\,\,\,eq(1)\\x+y+3z=-3\,\,\,eq(2)\\2x-y+2z=0\,\,\,eq(3)

Adding eq(1) and eq(2)

x-y+z=1\\x+y+3z=-3\\--------\\2x+4z=-2\,\,\,\,eq(4)\\

Adding eq(2) and eq(3)

x+y+3z=-3\\2x-y+2z=0\\----------\\3x+5z=-3\,\,\,eq(5)

Multiplying eq(4) by 3 and eq(5) by 2

6x+12z=-6\\6x+10z=-6\\-\,\,\,-\,\,\,\,\,\,\,\,\,\,\,\,\,\,+\\----------\\2z=0\\z=0

So, value of z =0

Putting value of z in eq(4)

2x+4z=-2\\2x+4(0)=-2\\2x=-2\\x=-1

So, value of x = -1

Now putting value of z=0 and x =-1 in equation 1

x-y+z=1\\-1-y+0=1\\-y=1+1\\-y=2\\y=-2

So, value of y = -2

So, solving the system we get, x= -1, y= -2 and z= 0

Keywords: Solve the system

Learn more about Solve the system at:

  • brainly.com/question/6075514
  • brainly.com/question/2386054
  • brainly.com/question/7361044

#learnwithBrainly

7 0
3 years ago
I need help please can’t seem to understand this
rewona [7]
True,
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2 years ago
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