A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
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b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Step-by-step explanation:
<u>The graph of a system of parallel lines will have no solutions. </u>
Because they will never intersect, having same slopes.
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<u>The graph of a system of equations with different slopes will have no solutions. </u>
Because they will intersect exactly once, having different slopes.
The square root of nine is three.
Answer:
x = 2.66666667
Step-by-step explanation:
3(x + 1) = 11
We multiply both x and 1 by 3 and get
3x + 3 = 11
Now we subtract 3 from both sides
3x + 3 - 3 = 11 - 3
3x = 8
Now divide both sides by 3
3x/3 = 8/3
x = 2.66666667
(っ◔◡◔)っ ♥ Hope It Helps ♥
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