3 years ago

list all the integer x that satisfy both the simultaneous linear inequalities 5-x<3 and x÷2 +3<5

Mathematics

1 answer:

Evgen [1.6K]3 years ago

6 0

For the first one any number less than 2 works
for the second on any number less than 4 works

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4 times x with an exponent of 2 plus 2 times y with an exponent of 4. X=-3 y=2

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Answer:

Step-by-step explanation:

Your equation is: $4*x^{2} +2 * y^{4}$

You also know that x = -3 and y = 2. You can rewrite the equation by substituting x and y with their actual values:

$4*(-3)^{2} +2 * 2^{4}$

First, you want to do the exponentiation (meaning you want to calculate $(-3)^{2}$ and $2^{4}$ parts). $(-3)^{2}$ equals 9 and $2^{4}$ equals 16.

So the equation now is:

$4*9+2*16$

Now you want to do multiplication. $4*9$ equals 36 and $2*16$ equals 32. So you're left with:

$36+32$

Which equals 68.

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