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2 years ago

Need help please, also about probabilities

Mathematics

1 answer:

liberstina [14]2 years ago

8 0

Answer:

Step-by-step explanation:

Good evening ,

_______________

a) p(rat)=1-(0,35+0,4+0,1)

b) p(cat ∪ hamster)=0,35+0,1

c) p(dog then dog)= (0,4)²

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Can y’all help me with this

Aleonysh [2.5K]

Answer:

it's the last one *25,000 J

Step-by-step explanation:

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2 years ago

6th-grade math DUE IN 5 MIN

Veseljchak [2.6K]

Answer:

272?

Step-by-step explanation:

10 x 8 = 80

12 x 16 = 192

192 + 80 = 272.

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2 years ago

1 2/3. 7/8 someone help me please

Ksivusya [100]

1 2/3 * 7/8...turn the mixed number to an improper fraction
5/3 * 7/8 = 35/24 = 1 11/24

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2 years ago

Read 2 more answers

The perimeter of a square is 88 feet. What is the length of one of its sides?

goldfiish [28.3K]

Answer:

A. 22 feet

Step-by-step explanation:

22 + 22 + 22 + 22 = 88 the formula is

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Hope this helps

5 0

2 years ago

Salaries of 49 college graduates who took a statistics course in college have a mean, x overbar, of $ 65 comma 300. Assuming a

Molodets [167]

Answer: $60,540< \mu$

Step-by-step explanation:

The confidence interval for population mean is given by :-

$\overline{x}-z^*\dfrac{\sigma}{\sqrt{n}}< \mu$

, where $\sigma$ = Population standard deviation.

n= sample size

$\overline{x}$ = Sample mean

z* = Critical z-value .

Given : $\sigma=\$17,000$

n= 49

$\overline{x}= \$65,300$

Two-tailed critical value for 95% confidence interval = $z^*=1.960$

Then, the 95% confidence interval would be :-

$65,300-(1.96)\dfrac{17000}{\sqrt{49}}< \mu$

$=65,300-(1.96)\dfrac{17000}{7}< \mu$

$=65,300-4760< \mu$

$=60,540< \mu$

Hence, the 95% confidence interval for estimating the population mean $(\mu)$ :

$60,540< \mu$

7 0

2 years ago