The confidence interval did give convincing evidence that there is difference in the population mean number of pairs of shoes for boys and girls at the school.
<h3>Why does the confidence
interval did give convincing evidence?</h3>
The interval is one that gave a good convincing evidence, based on the fact that the number 0 stands as NO difference ( (girls boys) and thus it is = 0 ).
It is also not not included in this interval and as such, it can mean that the difference in the mean number of shoes owned by girls and the mean number of shoes owned by boys is 0 .
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Answer:
The central idea of this passage is that the cat is lazy and manipulative. She doesn't work, but her cunningness and cuteness allow her consistent privileges.
Assuming your retirement is more than 2 years away, and that your car purchase is not before the end of the year, the shortest-term goal of those listed is ...
... d. add $200 to your savings account by the end of the year
_____
As a teenager, "short term" may be a matter of a week or two. As a middle-aged adult, both your life-lived and life-expectancy are somwhat longer, so "short-term" can be somewhat longer as well. In old age and failing health, "short-term" may again be a matter of a few weeks at most. Such concepts are tempered by perspective.
Answer:
a. 99.30% of the woman meet the height requirement
b. If all women are eligible except the shortest 1% and the tallest 2%, then height should be between 58.32 and 68.83
Explanation:
<em>According to the survey</em>, women's heights are normally distributed with mean 63.9 and standard deviation 2.4
a)
A branch of the military requires women's heights to be between 58 in and 80 in. We need to find the probabilities that heights fall between 58 in and 80 in in this distribution. We need to find z-scores of the values 58 in and 80 in. Z-score shows how many standard deviations far are the values from the mean. Therefore they subtracted from the mean and divided by the standard deviation:
z-score of 58 in=
= -2.458
z-score of 80 in=
= 6.708
In normal distribution 99.3% of the values have higher z-score than -2.458
0% of the values have higher z-score than 6.708. Therefore 99.3% of the woman meet the height requirement.
b)
To find the height requirement so that all women are eligible except the shortest 1% and the tallest 2%, we need to find the boundary z-score of the
shortest 1% and the tallest 2%. Thus, upper bound for z-score has to be 2.054 and lower bound is -2.326
Corresponding heights (H) can be found using the formula
and
Thus lower bound for height is 58.32 and
Upper bound for height is 68.83