Wea re given with <span>f(x)=ax^3+bx^2+cx+d </span> taking the first derivative <span>f′(x) = 3ax2 + 2bx + c substituting the conditions to the original equation </span><span>f(−3)=4=> -27a + 9b−3c+d </span><span>f(2)=0=>8a+4b+2c+d
So first you start by making the percent which is 20 a decimal (.20) . Then , you multiplu .20 by 800 and get 160 , or if you know 10% is 80 2 times that would be 20 percent . And 80 plus 80 is 160 .
