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jonny [76]
3 years ago
8

Jim's work evaluating 2 (three-fifths) cubed is shown below. 2 (three-fifths) cubed = 2 (StartFraction 3 cubed Over 5 EndFractio

n) = 2 (StartFraction 3 times 3 times 3 Over 5 EndFraction) = 2 (StartFraction 27 Over 5 EndFraction) = StartFraction 54 Over 5 EndFraction Which statement best describe Jim's first error? He did not multiply Three-fifths by 2 before applying the power. He did not apply the power to the denominator of Three-fifths. He did not evaluate 33 correctly. He did not multiply StartFraction 27 Over 5 EndFraction by 2 correctly.
Mathematics
2 answers:
sammy [17]3 years ago
6 0

Answer:

Jim's error is " He did not multiply Three-fifths by 2 before applying the power "

Step-by-step explanation:

Jim's evaluating expression is 2(\frac{3}{5})^3

To verify Jim's error :

Jim's steps are

2(\frac{3}{5})^3

=2(\frac{3^3}{5})

=2(\frac{3\times 3\times 3}{5})

=2(\frac{27}{5})

=\frac{54}{5}

Therefore 2(\frac{3}{5})^3=\frac{54}{5}

Jim's error is " He did not multiply Three-fifths by 2 before applying the power "

That is the corrected steps are

2(\frac{3}{5})^3

=2(\frac{3^3}{5^3})  ( using the property (\frac{a}{b})^m=\frac{a^m}{b^m} )

=2(\frac{3\times 3\times 3}{5\times 5\times 5})

=2(\frac{27}{125})

=\frac{54}{125}

2(\frac{3}{5})^3=\frac{54}{125}

SSSSS [86.1K]3 years ago
6 0

Answer:

the first option, he did not multiply 3/5 by 2 before applying the power.

Step-by-step explanation:

took the unit test

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