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2 years ago

Help with #14!!!!!!!

Mathematics

2 answers:

Charra [1.4K]2 years ago

6 0

-(-4) = 4, so the opposite, if I understand what they mean, would be -4.

Nina [5.8K]2 years ago

3 0

It is -4 becaus 2 negative signs makes it positive

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Step-by-step explanation:

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2 years ago

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2 years ago

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For the function f ( x ) = − 2 x + 3 , evaluate and simplify the difference quotient.

aev [14]

Answer:

fraction x-3/2 is your answer for Sure

Step-by-step explanation:

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2 years ago

Write and solve a system of equations for the situation described below. Define your variables and write your solution as a sent

Delicious77 [7]

N = nickels and q = quarters

0.05n + 0.25q = 1.90
n = 2q + 3

0.05(2q + 3) + 0.25q = 1.90
0.10q + 0.15 + 0.25q = 1.90
0.10q + 0.25q = 1.90 - 0.15
0.35q = 1.75
q = 1.75/0.35
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n = 2q + 3
n = 2(5) + 3
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2 years ago

Find lim ?x approaches 0 f(x+?x)-f(x)/?x where f(x) = 4x-3

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If $f(x)=4x-3$ :

$\displaystyle\lim_{\Delta x\to0}\frac{(4(x+\Delta x)-3)-(4x-3)}{\Delta x}=\lim_{\Delta x\to0}\frac{4\Delta x}{\Delta x}=4$

If $f(x)=4x^{-3}$ :

$\displaystyle\lim_{\Delta x\to0}\frac{\frac4{(x+\Delta x)^3}-\frac4{x^3}}{\Delta x}=\lim_{\Delta x\to0}\frac{\frac{4x^3-4(x+\Delta x)^3}{x^3(x+\Delta x)^3}}{\Delta x}$

$\displaystyle=\lim_{\Delta x\to0}\frac{4x^3-4(x^3+3x^2\Delta x+3x(\Delta x)^2+(\Delta x)^3)}{x^3\Delta x(x+\Delta x)^3}$

$\displaystyle=\lim_{\Delta x\to0}\frac{-12x^2\Delta x-12x(\Delta x)^2-4(\Delta x)^3}{x^3\Delta x(x+\Delta x)^3}=-\frac{12}{x^4}$

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3 years ago