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Kaylis [27]
3 years ago
8

Please help on this.. needs to be done

Mathematics
1 answer:
MrMuchimi3 years ago
6 0
I believe the answer is 221
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A line is perpendicular to y = - x - 2 and intersects the point (-5, 10)
Lady_Fox [76]

Answer:

y = x + 15

Step-by-step explanation:

If two lines are perpendicular to each other, they have opposite slopes.

The first line is y = - x - 2. Its slope is -1. A line perpendicular to this will have a slope of 1.

Plug this value (1) into your standard point-slope equation of y = mx + b.

y = 1x + b or y = x + b

To find b, we want to plug in a value that we know is on this line: in this case, it is (-5, 10). Plug in the x and y values into the x and y of the standard equation.

10 = (-5) + b

Simplify.

10 = -5 + b

Now, add 5 to both sides to isolate b.

15 = b

Plug this into your standard equation.

y = x + 15

This equation is perpendicular to your given equation (y = -x - 2) and contains point (-5, 10)

Hope this helps!

6 0
3 years ago
How do i do disss pls help​
masya89 [10]
Number one would be x=4, I hope this helps
8 0
3 years ago
CAN SOMEONE PLEASE HELP ME
zysi [14]

it is a rotation ........

5 0
3 years ago
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In aerobic respiration
jek_recluse [69]

the process of producing cellular energy involving oxygen. Cells break down food in the mitochondria in a long, multistep process that produces roughly 36 ATP. The first step in is glycolysis, the second is the citric acid cycle and the third is the electron transport system.

-Brightstorm

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3 years ago
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PLEASE HELP and Show your work please!!
bazaltina [42]

9514 1404 393

Answer:

  2)  3 pages per hour

  3)  4/29 km per minute

Step-by-step explanation:

Division by a fraction is the same as multiplication by the inverse of that fraction.

<h3>2) </h3>

  \dfrac{\ \dfrac{9}{4}\ }{\dfrac{3}{4}}=\dfrac{9}{4}\times\dfrac{4}{3}=\dfrac{36}{12}=\boxed{3\text{ pages per hour}}

__

<h3>3) </h3>

  \dfrac{2\text{ km}}{\dfrac{29}{2}\text{ min}}=2\times\dfrac{2}{29}\text{ km/min}=\boxed{\dfrac{4}{29}\text{ km/min}}

8 0
3 years ago
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