Which values are solutions to the inequality below? Check all that apply
2 answers:
Answer:
A, E, F
Step-by-step explanation:
With this question, it's mostly just trial and error.
<13 can be converted to 5.09901951<13, which is true.
<13 can be converted to 15.8429795<13, which is false.
<13 can be converted to 169<13, which is false.
<13 can be converted to 13.0384048<13, which is false.
<13 can be converted to 1<13, which is true.
<13 can be converted to 3.87298335<13, which is true.
Therefore, A, E and F are true.
**This question involves using inequalities and converting surds to numbers/decimals, which you may want to practice. I'm always happy to help!
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Answer:
6
Step-by-step explanation:
Since it's 5.56, you'll want to round UP because 5 is in the tenths and is closer to 6
2 ways: make a little divide tree based on how many times you can divide it. Like you have sqrt88 you know it can divide by 2. So its 2 and 44, and 44 can be broken to 2 and 22, then 2 and 11. 11 can’t be divided anymore.
Now choose numbers that are the same and pair them together. These go outside the radicand. You had three 2’s and one 11. So a 2 would go on the outside and the remaining 2 and 11 would be multiplied leaved 2sqrt22.
Another way is to divide by the highest squared number. Taking sqrt88 again. 4 would be the highest squared number. So 88 would be 4 and 22, then 2 and 11. Since you have a 4 which is a perfect square you put that squareroot outside. The inside would remain the same because it wouldn’t break down into perfect squares or pairs anymore. So that would be 2sqrt22.
Now choose numbers that are the same and pair them together. These go outside the radicand. You had three 2’s and one 11. So a 2 would go on the outside and the remaining 2 and 11 would be multiplied leaved 2sqrt22.
Another way is to divide by the highest squared number. Taking sqrt88 again. 4 would be the highest squared number. So 88 would be 4 and 22, then 2 and 11. Since you have a 4 which is a perfect square you put that squareroot outside. The inside would remain the same because it wouldn’t break down into perfect squares or pairs anymore. So that would be 2sqrt22.