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schepotkina [342]
3 years ago
12

What is the value of x?

Mathematics
1 answer:
dsp733 years ago
3 0

Answer:

I think its 5?

Step-by-step explanation:

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The length of a rectangle is 11 in. longer than its width. the perimeter of the rectangle is 86 in.write and solve an equation t
Tcecarenko [31]
I hope this helps you


width w


length w+11



perimeter =2 (width +length )


86=2 (w+w+11)


43=2w+11


32=2w


w=16

length = w+11=16+11=27
6 0
4 years ago
Which of the following theorems verifies that ABC ~ STU?
Lunna [17]

Answer:

B. AA

Step-by-step explanation:

The diagram given shows that two angles in ∆ABC are congruent to two corresponding angles in ∆STU.

Invariably, the third unknown angle of both triangles would also be equal going by the third angle theorem.

Thus, based on the AA Similarity Theorem which says that two triangles are similar to each other if two corresponding angles of one is congruent to two angles in the other, ∆ABC ~ ∆STU.

4 0
3 years ago
The pie chart represents the proportions of how Henry spent the £720 he took on holiday.
Oksana_A [137]

Answer:

£124

Step-by-step explanation:

first of all, you're meant to add all the figures given on the pie chart, which is 29+137+58+62+74 and that will give you a total of 360 degrees

so, you say 360 degrees is equal to the total amount of money he spent, which is £720, what about 62 degrees

therefore, you just do (62×720)÷360

that will give you £124

6 0
2 years ago
Please helppppp!!!!!
saul85 [17]

Answer:

right angle

Step-by-step explanation:

sorry if its wrong

5 0
3 years ago
Evaluate the triple integral.
Irina-Kira [14]

The definition of the set E gives you a natural choice for the limits in the integral:

\displaystyle \iiint_E y \, dV = \int_0^6 \int_0^x \int_{x-y}^{x+y} y \, dz \, dy \, dx

Computing the integral, we get

\displaystyle \iiint_E y \, dV = \int_0^6 \int_0^x y ((x+y)-(x-y)) \, dy \, dx = 2 \int_0^6 \int_0^x y^2 \, dy \, dx

\displaystyle \iiint_E y \, dV = 2 \int_0^6 \frac13 (x^3 - 0^3) \, dx = \frac23 \int_0^6 x^3 \, dx

\displaystyle \iiint_E y \, dV = \frac23 \cdot \frac14 (6^4 - 0^4) = \boxed{216}

6 0
2 years ago
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