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3 years ago

Four times the smallest of three consecutive integers is three more than three times the largest. What is the middle integer?

Mathematics

1 answer:

kozerog [31]3 years ago

3 0

Let, first integer is x.

Therefore, other two are x+1 , x+2 .

Now, mathematical expression of given conditions is :

4x + 3 = 3(x+2)

4x + 3 = 3x + 6

x = 3.

So, the consecutive numbers are 3 , 4 and 5.

Therefore, the middle integer is 4.

Hence, this is the required solution.

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-5x - 35= -15 -5x = 25 X =

Zigmanuir [339]

X= -5 because you divide -5x by -5 to get x alone so you have to 25/-5 which is -5

3 0

3 years ago

consider the function f(x) = x2 2x – 15. what are the x-intercepts of the function? left-most x-intercept: ( , 0) right-most x-i

eimsori [14]

we have

$f(x)=x^{2} +2x-15$

we know that

The x-intercept is the value of x when the value of the function is equal to zero

in this problem

Find the roots of the function

equate the function to zero

$x^{2} +2x-15=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2} +2x=15$

Complete the square. Remember to balance the equation by adding the same constants to each side

$x^{2} +2x+1=15+1$

$x^{2} +2x+1=16$

Rewrite as perfect squares

$(x+1)^{2}=16$

Square root both sides

$(x+1)=(+/-)\sqrt{16}$

$(x+1)=(+/-)4$

$x=-1(+/-)4$

$x1=-1+4=3$

$x2=-1-4=-5$

$x^{2} +2x-15=(x-3)(x+5)$

therefore

the answer is

the x-intercepts are the points $(3,0)$ and $(-5,0)$

3 0

3 years ago

Read 2 more answers

Will give brainliest please help -5x+4-x-1

Serjik [45]

Answer:

− 6 x + 3

Step-by-step explanation:

hope that helps :)

3 0

2 years ago

Find two consecutive odd integers such that 65 more than the lesser is four times the greate

lyudmila [28]

Let the lesser number be x and y the greater. Then

x + 65 = 4y , Also

y - x = 2
Adding:-

y + 65 = 4y + 2
63 = 3y
y = 21
and
x = 21-2 = 19

Answer the 2 odd numbers are 19 and 21.

8 0

3 years ago

Use the diagram to determine which statement is true

hichkok12 [17]

A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9

B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6

C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16

D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25

The answer is D.

5 0

3 years ago

Read 2 more answers