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4 years ago

Four times the smallest of three consecutive integers is three more than three times the largest. What is the middle integer?

Mathematics

1 answer:

kozerog [31]4 years ago

3 0

Let, first integer is x.

Therefore, other two are x+1 , x+2 .

Now, mathematical expression of given conditions is :

4x + 3 = 3(x+2)

4x + 3 = 3x + 6

x = 3.

So, the consecutive numbers are 3 , 4 and 5.

Therefore, the middle integer is 4.

Hence, this is the required solution.

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Step-by-step explanation:

We want to find the point in QI at which the line with the equation:

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Intersect a circle with a radius of 3 and a center of (0, 5).

First, write the equation of a circle. The equation for a circle is given by:

$(x-h)^2+(y-k)^2=r^2$

Where (h, k) is the center and r is the radius.

Since our center is (0, 5), h = 0 and k = 5. The radius is 3. So, r = 3. Substitute:

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$x^2+(0.5x)^2=9$

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Solve for x:

$\displaystyle \begin{aligned} x^2&=\frac{36}{5} \\ x&=\pm\sqrt{\frac{36}{5}} \\ x&\Rightarrow \frac{6}{\sqrt{5}}=\frac{6\sqrt{5}}{5}\approx2.68\end{aligned}$

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To find the y-coordinate, substitute the x-value back into either equation. Using the linear equation:

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