Write this polynomial in standard form (x+2)(x+5)

Mathematics

2 answers:

oksian1 [2.3K]3 years ago

8 0

Answer:

Step-by-step explanation:

nexus9112 [7]3 years ago

7 0

(X+2) (x+5)

Multiply each term in the first parentheses by each term in the second parentheses (FOIL)

X•x+5x+2x+2x5

Calculate the product

X^2+5x+2x+2x5

Multiple the number

X^2+5x+2x+10

Collect like terms

X^2+7x+10

And the solution is

X^2+7x+10

I hope and my answer helps you

You might be interested in

Complete this statement 27ax^2+18ax+45a=9a( )

aleksklad [387]

27a² + 18ax + 45a = 9a(3a + 2x + 5)

----------------------------------------------------------------------------
This missing part is 3a + 2x + 5.
----------------------------------------------------------------------------

5 0

3 years ago

Solve for x<br>6x²+2x-12

dem82 [27]

Answer:

Step-by-step explanation:

Solving for x means you have to factor. First factor out the GCF of 2 to get:

$2(3x^2+x-6)$ and now we'll factor using the regular old method of ac and then factoring by grouping. In our polynomial, a = 3, b = 1, c = -6. Therefore, a times c is 3 * -6 which is -18. We need some combinations of the factors of 18 that will add to give us 1, the b term in the middle. The factors of 18 are:

1, 18

2, 9

3, 6 and that's it. Hm...it seems that won't work, so let's throw this into the quadratic formula, going back to the original and a = 6, b = 2 and c = -12:

$x=\frac{-2+/-\sqrt{2^2-4(6)(-12)} }{2(6)}$ and

$x=\frac{-2+/-\sqrt{4+288} }{12}$ and

$x=\frac{-2+/-\sqrt{292} }{12}$ and

$x=\frac{-2+/-\sqrt{4*73} }{12}$ and

$x=\frac{-2+/-2\sqrt{73} }{12}$ which finally simplifies to

$x=\frac{-1+/-\sqrt{73} }{6}$ No wonder that didn't factor using the traditional method of factoring! We could have found that out by finding first the value of the discriminant, but oh well!

8 0

3 years ago

How much money would you have in your savings balance after 3 years if you initially invested $900 and had an interest rate of 1

denis-greek [22]

assuming simple interest

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$900\\ r=rate\to 1\%\to \frac{1}{100}\dotfill &0.01\\ t=years\dotfill &3 \end{cases} \\\\\\ A=900[1+(0.01)(3)]\implies A=900(1.03)\implies A=927$