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Sveta_85 [38]
4 years ago
13

Maddy received $60 for her birthday and decided to go shopping. She bought 2 shirts priced at $12.25 each, a necklace for $8.50,

and a pair of shoes for $22.75. If all the prices included tax, and she gave the cashier all of her birthday money, how much change did she get back? * $4.25 $5.25 $16.50 $8.25
Mathematics
2 answers:
m_a_m_a [10]4 years ago
6 0

Answer:

4.31

Step-by-step explanation:

you have to subtract the tax, i didnt yet.

kompoz [17]4 years ago
5 0

Answer:

$4.25

Step-by-step explanation:

Add all the money she spent on things

(12.25*2) + 8.5 + 22.75 = 55.75

60 - 55.75 = 4.25

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Answer:

\int\limits {5^x} \, dx = \frac{5^x}{ln\ x} + c

Step-by-step explanation:

Note that the integral of 5^x is not \frac{1}{6}x^6 + c

The solution is as follows:

Given

5^x

Required

Integrate

Represent the given expression using integral notation

\int\limits {5^x} \, dx

This question can't be solved directly;

We'll make use of exponential rules which states;

\int\limits {a^x} \, dx = \frac{a^x}{ln\ x} + c

By comparing \int\limits {5^x} \, dx with \int\limits {a^x} \, dx;

we can substitute 5 for a;

Hence, the expression \int\limits {a^x} \, dx = \frac{a^x}{ln\ x} + c becomes

\int\limits {5^x} \, dx = \frac{5^x}{ln\ x} + c

-------------------------------------------------------------------------------------

However, the integral of x^5 is \frac{1}{6}x^6 + c

This is shown below:

Given that x^5

Applying power rule;

Power rule states that

\int\limits{x^n}\ dx = \frac{x^{n+1}}{n+1} + c

In this case (x^5), n = 5;

So, \int\limits{x^n}\ dx= \frac{x^{n+1}}{n+1} + c

becomes

\int\limits{x^5}\ dx = \frac{x^{5+1}}{5+1} + c

\int\limits{x^5}\ dx = \frac{x^{6}}{6} + c

\int\limits{x^5}\ dx= \frac{x^{6}}{6} + c

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