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Ronch [10]
3 years ago
13

Let f(x)=−x√3 . What is the average rate of change of f(x) from 8 to 64?

Mathematics
1 answer:
Fed [463]3 years ago
5 0

Average rate of change of the function: -\sqrt{3}

Step-by-step explanation:

The average rate of change of a function f(x) can be calculated as:

r=\frac{f(x_2)-f(x_1)}{x_2-x_1}

where:

x_1, x_2 are the x-values of the interval taken into account to evaluate the rate of change of the function

f(x_1),f(x_2) are the values of the function at those points

In this problem, we have:

x_1=8\\x_2=64

The function is f(x)=-x\sqrt{3}, so

f(x_1)=f(8)=-8\sqrt{3}\\f(x_2)=f(64)=-64\sqrt{3}

So, the average rate of change in this interval is:

r=\frac{-64\sqrt{3}-(-8\sqrt{3})}{64-8}=\frac{-56\sqrt{3}}{56}=-\sqrt{3}

Learn more about rates of change:

brainly.com/question/4152194

brainly.com/question/12941985

#LearnwithBrainly

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Answer:

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Step-by-step explanation:

Given equation is \frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}

Factor denominators then solve by making denominators equal

\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}

\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}

\frac{y\left(y+4\right)-4\left(y-4\right)}{\left(y-4\right)\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}

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take squar root of both sides

y=\pm \sqrt{-7}

y=\pm i \sqrt{7}

Hence final answer is y=\pm i \sqrt{7}.

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