Answer:
(2 x - 3)^2 thus it's True
Step-by-step explanation:
Factor the following:
4 x^2 - 12 x + 9
Factor the quadratic 4 x^2 - 12 x + 9. The coefficient of x^2 is 4 and the constant term is 9. The product of 4 and 9 is 36. The factors of 36 which sum to -12 are -6 and -6. So 4 x^2 - 12 x + 9 = 4 x^2 - 6 x - 6 x + 9 = 2 x (2 x - 3) - 3 (2 x - 3):
2 x (2 x - 3) - 3 (2 x - 3)
Factor 2 x - 3 from 2 x (2 x - 3) - 3 (2 x - 3):
(2 x - 3) (2 x - 3)
(2 x - 3) (2 x - 3) = (2 x - 3)^2:
Answer: (2 x - 3)^2
I'll try it.
I just went through this twice on scratch paper. The first time was to
see if I could do it, and the second time was because the first result
I got was ridiculous. But I think I got it.
You said <span><u>3sin²(x) = cos²(x)</u>
Use this trig identity: sin²(x) = 1 - cos²(x)
Plug it into the original equation for (x).
3(1 - cos²(x) ) = cos²(x)
Remove parentheses on the left: 3 - 3cos²(x) = cos²(x)
Add 3cos²(x) to each side: 3 = 4cos²(x)
Divide each side by 4 : 3/4 = cos²(x)
Take the square root of each side: <em>cos(x) = (√3) / 2</em> .
There it is ... the cosine of the unknown angle.
Now you just go look it up in a book with a table cosines,
or else pinch it through your computer or your calculator,
or else just remember that you've learned that
cos( <em><u>30°</u></em> ) = </span><span><span>(√3) / 2 </span>.
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We are given with a equation of Circle and we need to find it's radius and it's equation in standard form . But , let's recall , the standard equation of a circle is
where <em>(h,k)</em> is the centre of the circle and radius is <em>r</em> . Proceeding further ;
Collecting <em>x</em> terms , y terms and transposing the constant to RHS ;
Now , as in standard equation their is a whole square , so we need to develop a whole square in LHS , for which we will use completing the square method , as coefficient of x² and y² is 1 , so adding 121 and 36 to LHS and RHS .
On comparing this with the standard equation , we got our centre at <em>(-11,-6)</em> and radius is <em>18 units </em>
Answer:
x=-5
Step-by-step explanation:
Vertical lines have the same x value all the time. They are of the form x=
Since it passes through the point (-5,-2) the x value must be -5
x=-5