Question

A cylindrical can containing pieces of fruit is filled to the top with syrup before being sealed. The base of the can has an area of 75 cm2, and the height of the can is 10cm. If 110 cm3 of syrup is needed to fill the can to the top, what is the total volume of the pieces of fruit in the can?

Answer 1

Answer:

The total volume of the pieces of fruit in the can is $640\ cm^{3}$

Step-by-step explanation:

step 1

Find the volume of the cylindrical can

The volume of the can  is equal to

$V=BH$

where

B is the area of the base of the can

H is the height of the can

we have

$B=75\ cm^{2}$

$H=10\ cm$

substitute

$V=(75)(10)=750\ cm^{3}$

step 2

Find the volume of the pieces of fruit in the can

The volume of the pieces of fruit in the can is equal to subtract  the volume of syrup from the volume of the can

$750\ cm^{3}-110\ cm^{3}=640\ cm^{3}$

Answer 2

Answer:

I think the answer is "C"

Step-by-step explanation:

640 cm3

V = base × height

V = 75 cm2 × 10 cm

V = 750 cm3

Vfruit = Vtotal − Vsyrup

Vfruit = 750 cm3 − 110 cm3 = 640 cm3