Answer:
if ∠ABC = 180°,
then, 2x∠ADC = ∠ABC ( angles subtended by an arc at the center is double the angle subtended it at any point on the remaining part if the circle)
{ please read the theorem carefully as i know u wont be able to understand it at first try :) }
therefore ∠ADC = 90°
In function notation (f(x)=mx+b) m represents the slope and b represents the y-intercept.
In a straight horizontal line the slope is always 0. This cancels out the 'x' factor so you get f(x)=b.
To find b you simply look at where the line crosses the y-axis. in this case it crosses at 2.
When you plug in the y-intercept you get f(x)=2
Answer:
4. false
5. false
Step-by-step explanation:
4. so sometimes it is false and sometimes true; i went with false just because sometimes it is not true and it not being true some of the time is definitely dominant.
5. simple. lol
Answer:
The last dose will be administered at 6 P.M.
Step-by-step explanation:
This problem can be solved by direct rule of three.
The problem states that each tablet has 75mg of medication, and that every 3 hours, 2 tablets are administered.
So
1 tablet - 75mg of medication
2 tabets - xmg of medication
x = 150mg
It means that in each dose, 150mg of medication are administed.
At 6am, as the first dose is administered, the patient will have taken 150mg of medication. In how many doses will the patient have been administed 750mg?
1 dose - 150mg
x doses - 750mg
150x = 750
x = 5 doses.
The doses are administed in intervals of 3 hours. After the first dose, there will be 4 doses remaining. So it will take 4*3 = 12 hours to administer 4 doses.
So, if the first dose is administed at 6am, the last is going to be administed at 6h+12h = 18h = 6P.M.
Answer and Step-by-step explanation: The <u>critical</u> <u>value</u> for a desired confidence level is the distance where you must go above and below the center of distribution to obtain an area of the desired level.
Each sample has a different degree of freedom and critical value.
To determine critical value:
1) Calculate degree of freedom: df = n - 1
2) Subtract the level per 100%;
3) Divide the result by 2 tails;
4) Use calculator or table to find the critical value t*;
For n = 5 Level = 90%:
df = 4
t = 
= 0.05
Using t-table:
t* = 2.132
n = 13 Level = 95%:
df = 12
t = 
= 0.025
Then:
t* = 2.160
n = 22 Level = 98%
df = 21
t = 
= 0.01
t* = 2.819
n = 15 Level = 99%
df = 14
t = 
= 0.005
t* = 2.977
The critical values and degree of freedom are:
sample size level df critical value
5 90% 4 2.132
13 95% 12 2.160
22 98% 21 2.819
15 99% 14 2.977
