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3 years ago

Jeremiah rounded a number 8.7 what could the original number have been

Mathematics

2 answers:

Fiesta28 [93]3 years ago

6 0

The original could have been 8.66

vlabodo [156]3 years ago

3 0

The number could have been 8.699999999 so yeah there

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Which information about the coordinates of G and H will prove that GH is a median of AABC?

Annette [7]

Answer:

G (3,-4) ; H (8,1)

Step-by-step explanation:

Midpoint formula:

(x₁ + x₂ / 2 , y₁ + y₂ / 2)

For G (Points B and A):

(3 + 3 / 2 , 1 + (-9) / 2)

(6/2 , -8 / 2)

(3,-4)

For H (Points B and C):

(3 + 13 / 2 , 1 + 1 / 2)

(16 / 2 , 2 / 2)

(8,1)

3 0

4 years ago

Suzanne ran 334 miles in the morning and 412 miles in the afternoon. How many kilometers did she run altogether? Assume 1 mile

morpeh [17]

1193.6 because 334+412=746 and 746*1.6=1193.6

8 0

3 years ago

Given the trigonometric function value of theata Find the exact value of all remaining trigonometric function csc(theata)= 7

Monica [59]

I don’t understand why people are sending files as answer

8 0

2 years ago

Find the area of the shaded region

o-na [289]

so hmmm let's get the area of the whole hexagon, and then get the area of the circle inside it, then <u>subtract the area of the circle from that of the hexagon's</u>, what's leftover is what we didn't subtract, namely the shaded part.

$\textit{area of a regular polygon}\\\\ A=\cfrac{1}{4}ns^2\cot\stackrel{\stackrel{degrees}{\downarrow }}{\left( \frac{180}{n} \right)}~ \begin{cases} n=\textit{number of sides}\\ s=\textit{length of a side}\\[-0.5em] \hrulefill\\ n=\stackrel{hexagon}{6}\\ s=\frac{9}{2} \end{cases}\implies A=\cfrac{1}{4}(6)\left( \cfrac{9}{2} \right)^2 \cot\left( \cfrac{180}{6} \right)$

$A=\cfrac{1}{4}(6)\cfrac{9^2}{2^2} \cot(30^o)\implies A=\cfrac{243}{8}\cot(30^o)\implies A=\cfrac{243\sqrt{3}}{8} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=\frac{4}{5} \end{cases}\implies A=\pi \left( \cfrac{4}{5} \right)^2\implies A=\cfrac{16\pi }{25} \\\\[-0.35em] ~\dotfill$

$\stackrel{\textit{area of the hexagon}}{\cfrac{243\sqrt{3}}{8}}~~ - ~~\stackrel{\textit{area of the circle}}{\cfrac{16\pi }{25}}\implies \cfrac{6075\sqrt{3}-128\pi }{200}$

5 0

2 years ago

Step by step explanation please!!

elixir [45]

Answer:

what do you mean on the question?

Step-by-step explanation:

3 0

3 years ago