Answer:
Amount of Winter sealer for 2 coats[in square feet] = 576 square feet
Step-by-step explanation:
Given:
Length of drive way at garage door = 12 feet
Length of drive way at street = 20 feet
Length of total driveway = 18 feet
Find:
Amount of Winter sealer for 2 coats[in square feet]
Computation:
Amount of Winter sealer for 2 coats[in square feet] = 2[Area of trapezoid]
Amount of Winter sealer for 2 coats[in square feet] = 2[(1/2)(Sum of parallel side)(Height)]
Amount of Winter sealer for 2 coats[in square feet] = 2[(1/2)(12 + 20)(18)]
Amount of Winter sealer for 2 coats[in square feet] = 2[(1/2)(32)(18)]
Amount of Winter sealer for 2 coats[in square feet] = 32 x 18
Amount of Winter sealer for 2 coats[in square feet] = 576 square feet
The formula for perimeter is:
<span>P = 2 h + 2 w</span>
where P is perimeter = 120 cm, h is height, w is width
we are also given that: h = (2/3) w, therefore:
P = 2 (2/3) w + 2 w = 120
(4/3) w + 2 w = 120
w = 36 cm
Therefore l is:
l = (2/3) w = 24 cm
<span>Hence the dimension should be 24cm by 36 cm</span>
D. y=mx+b. m being slope and b being the y intercept. so the equation for the line is y=3x+2 and to be parallel your m must be the same number so D. 3x
Answer:
x = (-5 ± 2√10) / 3
Step-by-step explanation:
5 − 10x − 3x² = 0
Write in standard form:
-3x² − 10x + 5 = 0
Solve with quadratic formula:
x = [ -b ± √(b² − 4ac) ] / 2a
x = [ -(-10) ± √((-10)² − 4(-3)(5)) ] / 2(-3)
x = [ 10 ± √(100 + 60) ] / -6
x = (10 ± 4√10) / -6
x = (-5 ± 2√10) / 3
