Answer:
The remainder is 2.
Step-by-step explanation:
Use modular arithmetic.
If the remainder is x then 8^33 mod 6 = x.
8^3 = 512 = 2 mod 6
8^6 = (8^3 * 8^3) mod 6 = (2*2) mod 6 = 4 mod 6
8^30 mod 6 = (8^6)^5 mod 6 = 4^5 mod 6 = 1024 mod 6
= 4 mod 6.
Finally 8^33 mod 6 = (8^3 * 8^30) mod 6 = (2 * 4) mod 6
= 8 mod 6 = 2.
Find the least common multiples of 4, 10, 12, 15
multiples of 4:
4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80
multiples of 10: 10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120
multiples of 12: 12, 24, 36, 48, 60, 72, 84, 96, 108, 120
multiples of 15: 15, 30, 45, 60, 75, 90, 105, 120, 135, 150
The least common multiple of 4, 10, 12, and 15 is 60.
4 x 15 = 60
10 x 6 = 60
12 x 5 = 60
15 x 4 = 60
If the weight of the object on Earth is presented as e and it is stated in this item that the weight of the object in the mass is only 1/6 of it then, the mass of the object in the moon is e/6. Thus, the answer is letter B. m = e/6.
Answer:
(12, -23)
Step-by-step explanation:
to find x, substitute the value of y into y
-2x+1=-3x+13
collecting like terms
-2x+3x=13-1
x=12
to find y substitute the value x=12 into any of the equation
y=-3x+13
y=-3(12) +13
y= -36+13
y=-23
