X^5-15x^4y+90x^3y^2-270x^2y^3+405xy^4-243y^5
Step-by-step explanation:
By Pythagoras' Theorem,
where c is always the largest number.
a and b can be interchangeable between the 2nd largest and the 3rd largest numbers.
Given a = 8, b = 15 and c = 17,
Since c^2 = a^2 + b^2 , 8 , 15 and 17 are pythagorean triplets.
Now let's move on to 9, 40 and 41.
Since c^2 = a^2 + b^2 , 9 , 40 and 41 are pythagorean triplets.
Last let's move on to 4,7 and 8.
Since a^2+b^2 IS NOT EQUAL to c^2, 4,7 and 8 ARE NOT pythagorean triplets.
Answer: -37
Step-by-step explanation:
6 more than a number would make an equation of 6+x=-31. Subtract 6 on both sides to get x=-37
Move a graph c units to right, minus c from every x
move a graph c units up, add c to every x
so basically
move 5 left means move -5 right or minus -5 from every x or add 5 to every x
move 3 up means add 3 to whole function
basically add 5 to every x and 3 to the whole function
example
if you had y=mx+b, then the translated function would be y=m(x+5)+b+3