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skad [1K]
2 years ago
15

Find the area of each of these rectangles

Mathematics
1 answer:
Nadya [2.5K]2 years ago
6 0
A) 5 square root (2) units square
b) 6 units square
c) 36 units square
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The cost price of a box and a pen is Rs 80 The box is sold at 10% profit and the pen is sold at 20% loss. If the selling price o
uysha [10]

Answer:

61.84%

Step-by-step explanation:

Let the cost of the box be x. Since the price of the box and the pen is Rs 80, the pen's price can be represented as 80 - x. The box is sold at a ten percent profit, and an added ten percent is equal to 1.1. Therefore, the price the box sells at is 1.1(x). A 20% loss is the same a keeping 80% or multiplying by 0.8. This means the pen sold at 0.8(80 - x). Now, we are given the box went for Rs 28 more than the pen, so we can create an equation:

1.1x = 0.8(80 - x) + 28

We can simplify and solve:

1.1x = 64 - 0.8x + 28

1.9x = 92

x = 92/1.9

x = 920/19

The cost of the box after the increase would be 1.1(920/19) and the pen would be 0.8(80 - 920/19).

The sum of these two can be written as a percent x of 80.

80x = 0.8(80 - 920/19) + 1.1(920/19)

80x = 64 - 0.8(920/19) + 1.1(920/9)

80x = 64 - 0.3(920/19)

80x = 64 - 276/19

80x = 940/19

x = 940/1520

x = 0.6184

This is 61.84%

4 0
3 years ago
Brainliest + Points!
andre [41]

Answer:

Step-by-step explanation:

since you are already given the formula just plug in the numbers.

the only tricky part is r=rate must be in decimal form!!!

I=4,000(.035)(2)

I=280 (answer)

8 0
3 years ago
Solve for the unknown variable 5/3(4x-5)=4x-1/3
charle [14.2K]

Answer:

x=3

Step-by-step explanation:

its should be equal

6 0
3 years ago
Read 2 more answers
Find the point-slope form of the equation of the line passing through the points (–1, –3) and (4, 1).
IrinaK [193]
The answer is given above

5 0
3 years ago
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If $8700 is invested at 3% annual simple interest, how much should be invested at 6% annual simple interest so that the total ye
True [87]
First off, see  how much 8700 as principal, yields at 3% APR
that is \bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$8700\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &1
\end{cases}

it will yield some amount

subtract that amount from 393
the difference is how much the yield will be on the 6% investment
so

\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\quad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$8700\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &1
\end{cases}
\\\\\\
\implies \boxed{?}\\\\
-----------------------------\\\\
\textit{how much to invest at 6\%?}
\\\\\\


\bf \qquad \textit{Simple Interest Earned}\\\\
(393-\boxed{?}) = Prt\quad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
t=years\to &1
\end{cases}
\\\\\\
\textit{solve for "P", to see how much should the Principal be}\\\\
\textit{keep in mind that }P+\boxed{?}=393\leftarrow \textit{both yields added}
6 0
3 years ago
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