3 years ago

4×3-(2×3-16÷4) the answer with work

Mathematics

2 answers:

Elena-2011 [213]3 years ago

4 0

This is what I got as my answer hope it helps!

Reika [66]3 years ago

3 0

Answer:

Step-by-step explanation:

2x3=6

16/4=4

4x3-(6-4)

6-4=2

4x3-(2)

4x3=12

12-(2)

12-2=10

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Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).

Oduvanchick [21]

For two complex numbers $z_1=re^{i\theta}=r(\cos\theta+i\sin\theta)$ and $z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi)$ , the product is

$z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))$

That is, you multiply the moduli and add the arguments. You have $z_1=7e^{i40^\circ}$ and $z_2=6e^{i145^\circ}$ , so the product is

$z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}$