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sleet_krkn [62]
2 years ago
15

Suppose that the width of a certain rectangle is 1 inch more than one-fourth of its length. The perimeter of the rectangle is 52

inches. Find the length and width of the rectangle.
Mathematics
1 answer:
zalisa [80]2 years ago
7 0

Answer:

Length = 20

Width = 6

Step-by-step explanation:

Let the length of the rectangle be l inch, so, its width

w= (\frac{1}{4}l+1)

So the perimeter equals:

P= 2l+2w=2l+2(\frac{1}{4}l+1)=2l+\frac{1}{2}l+2=\frac{5}{2}l+2

52= \frac{5}{2}l+2

50 = \frac{5}{2}l    100=5l      20 = l

Hence width:

w = (\frac{1}{4}l+1)

w=5+1 = 6

Length = 20

Width = 6

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