Question

Suppose that the width of a certain rectangle is 1 inch more than one-fourth of its length. The perimeter of the rectangle is 52 inches. Find the length and width of the rectangle.

Answer 1

Answer:

Length = 20

Width = 6

Step-by-step explanation:

Let the length of the rectangle be l inch, so, its width

$w= (\frac{1}{4}l+1)$

So the perimeter equals:

$P= 2l+2w=2l+2(\frac{1}{4}l+1)=2l+\frac{1}{2}l+2=\frac{5}{2}l+2$

$52= \frac{5}{2}l+2$

$50 = \frac{5}{2}l$    $100=5l$      $20 = l$

Hence width:

$w = (\frac{1}{4}l+1)$

$w=5+1 = 6$

Length = 20

Width = 6