Ask question

Ask question

All categories

Zigmanuir [339]

3 years ago

8

What is the base of a triangle with an area of 36 square centimeters and a height of 9 centimeters?

2 answers:

andrew-mc [135]3 years ago

8 0

Area of a triangle = 1/2bh

the height is 9 centimeters

multiply 36 with 2: 36 x 2 = 72

72/9 = 8

the length is 8 centimeters

hope this helps

Levart [38]3 years ago

4 0

Area=1/2Base*Height
36=1/2Base*9
Base=8cm

You might be interested in

To solve a system of inequalities, you just need to graph each inequality and see which points are in the overlap of the graphs.

Juli2301 [7.4K]

The answer is true. Apex

6 0

3 years ago

Read 2 more answers

1. an alloy contains zinc and copper in the ratio of 7:9 find weight of copper of it had 31.5 kgs of zinc.

m_a_m_a [10]

Answer:

Step-by-step explanation:

Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.

If the weight of an alloy = x kgs

Then weight of copper = $\frac{9}{7+9}\times (x)$

= $\frac{9}{16}\times (x)$

And the weight of zinc = $\frac{7}{7+9}\times (x)$

= $\frac{7}{16}\times (x)$

If the weight of zinc = 31.5 kg

31.5 = $\frac{7}{16}\times (x)$

x = $\frac{16\times 31.5}{7}$

x = 72 kgs

Therefore, weight of copper = $\frac{9}{16}\times (72)$

= 40.5 kgs

2). i). 2 : 3 = $\frac{2}{3}$

4 : 5 = $\frac{4}{5}$

Now we will equalize the denominators of each fraction to compare the ratios.

$\frac{2}{3}\times \frac{5}{5}$ = $\frac{10}{15}$

$\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}$

Since, $\frac{12}{15}>\frac{10}{15}$

Therefore, 4 : 5 > 2 : 3

ii). 11 : 19 = $\frac{11}{19}$

19 : 21 = $\frac{19}{21}$

By equalizing denominators of the given fractions,

$\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}$

And $\frac{19}{21}\times \frac{19}{19}=\frac{361}{399}$

Since, $\frac{361}{399}>\frac{231}{399}$

Therefore, 19 : 21 > 11 : 19

iii). $\frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}$

$=\frac{3}{2}$

$\frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}$

= $\frac{4}{3}$

Now we equalize the denominators of the fractions,

$\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}$

And $\frac{4}{3}\times \frac{2}{2}=\frac{8}{6}$

Since $\frac{9}{6}>\frac{8}{6}$

Therefore, $\frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4}$ will be the answer.

IV). $1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}$

$=\frac{6}{5}\times \frac{3}{4}$

$=\frac{18}{20}$

$=\frac{9}{10}$

Similarly, $\frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}$

$=\frac{4}{15}$

By equalizing the denominators,

$\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}$

Similarly, $\frac{4}{15}\times \frac{20}{20}=\frac{80}{300}$

Since $\frac{270}{300}>\frac{80}{300}$

Therefore, $1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}$

V). If a : b = 6 : 5

$\frac{a}{b}=\frac{6}{5}$

$=\frac{6}{5}\times \frac{2}{2}$

$=\frac{12}{10}$

And b : c = 10 : 9

$\frac{b}{c}=\frac{10}{9}$

Since a : b = 12 : 10

And b : c = 10 : 9

Since b = 10 is common in both the ratios,

Therefore, combined form of the ratios will be,

a : b : c = 12 : 10 : 9

7 0

3 years ago

What is the solution set for this inequality? |3x+3|≤9 Graph the solution set on the number line.

soldi70 [24.7K]

Answer:

Step-by-step explanation:

because it's an absolute value inequality, there are two inequalities to solve

3x+3 ≤ 9 and 3x+3 ≥ -9, now we solve them separately

x ≤ 3 and x ≥ -4, which is -4 ≤ x ≤ 3

8 0

4 years ago

Read 2 more answers

HELPPP!! I’ll mark brainliest!!

Sedaia [141]

Answer:

A

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

If 27y is a multiple of 9 where y is a digit . What is the minimum value of Y.

stiv31 [10]

<h3>Answer: 0</h3>

Explanation:

The single digits are {0,1,2,3,4,5,6,7,8,9}

So naturally 0 is the first thing to test.

The number 270 is a multiple of 9 because 9*30 = 270. The digits of 270 add to 2+7+0 = 9 showing that it's a multiple of 9. Refer to the "divisibility by 9 rule".

The next possible value of y will be 9 units higher than y = 0, so we go for y = 9. Meaning that 279 is also a multiple of 9 (because 2+7+9 = 18 is a multiple of 9).

4 0

2 years ago