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VashaNatasha [74]
3 years ago
10

What is the first and last value of i to be displayed by the following code snippet? int n = 20; for (int i = 0; i <= n; i++)

{ for (int j = 0; j <= i; j++) { System.out.println("" + i); } }
Computers and Technology
1 answer:
frutty [35]3 years ago
6 0

Answer:

The first value of i is 0 and last value of i is 20.

Explanation:

The following are the description of a given loop.

  • In this problem, there are two loops one is the internal loop and the other is the external loop
  • In the outer loop, the value of " i" is initialized with "0" So the first value is printed 0 in the console.
  • For one value of "i" all the inner loop is executed.
  • The loop is executed is less equal to 20 that's why the last value of "i" is printed 20 in the console window.

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Answer:

Explanation:

Before we go deep into this question lets have some brief knowledge on parallel execution, parallel processing and multi tasking.

Parallel Execution : in this two or more tasks or program can be executed parallel or simultaneously.

For example if there are two processors and four programs to be executed then it executes two at a time.

Multi tasking: in this two or more tasks can be performed simultaneously switching between them without exiting any application.

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Multi Threading: It is splitting up the program into different threads.If the contents in the program are independent on each other then the program can be split into multi threads and can be processed.

Multi threading in multi core or processing unit : In this threads are executed parallel or simultaneously in different processes.

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Multi threaded program in single core unit : In this, program is multi threaded where as threads cannot execute parallel or simultaneously. they sholud be executed by the same processor. So they should wait in queue

Ex: consider three tasks of 6 secs each and multi threaded each into three threads of two seconds.

Task1 3secs > task2 3secs > task3 3 secs it repeats until each task is completed

Total time taken is 3+3+3+3+3+3+3+3+3 is 18seconds...

If they are executed one by one without multi threading total execution time has no change..

Where as multi threading program has its advantages if different threads are executed at different place..

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Information Sharing, message passing, Modularity.

In shared memory inter process communication processes shares the memory between each other.

In message passing communication process communicates like request and replies for information and resources.

Interlocking is due to error in resource sharing and information sharing. It results in system collapse.

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In single core there will be a single processor, processing multi threaded program as it can access all the memory contents there will be no problem of process communication. Where as in multi core systems different processes may compete for same memory or resource.

In single core systems inter process communication makes things complex and these complexity is not much useful in any of the improvement in performance.

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