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Kipish [7]
3 years ago
7

Explain why the x-coordinates of the points where the graphs of the equations y = 2−x and y = 8x+4 intersect are the solutions o

f the equation 2−x = 8x+4. part
b.make tables to find the solution to 2−x = 8x+4. take the integer values of x between −3 and 3. part
c.how can you solve the equation 2−x = 8x+4 graphically?

Mathematics
1 answer:
Luda [366]3 years ago
4 0
Part 1)
We have two lines:  y = 2-x   and   y = 8x+4
Given two simultaneous equations that are both required to be true.
the solution is the points where the lines cross
Which is where the two equations are equal
Thus the solution that works for both equations is when
2-x = 8x+4
because
where that is true is where the two lines will cross and that is the common point that satisfies both equations.

Part 2) Make tables to find the solution to 2−x = 8x+4. take the integer values of x between −3 and 3

see the attached table
The table shows that none of the integers from [-3,3] work because in no case does
<span>2-x = 8x+4
</span>
To find the solution we need to rearrange the equation to the form x=n
2-x =8x+4
8x+x=2-4
9x=-2
x=-2/9

 The only point that satisfies both equations is
where
 x = -2/9
Find y:
   y = 2-x  = 2 - (-2/9) = 2 + 2/9 = 20/9
Verify we get the same in the other equation
y = 8x+4   =  8(-2/9) + 4 = 20/9 
Thus the only actual solution, being the point where the lines cross,
 is the point (-2/9, 20/9)------> (-0.22,2.22)

Part 3) how can you solve the equation 2−x = 8x+4 graphically?
<span>The point on the graph where the lines cross is the solution to the system of equations
</span>
using a graph tool
see the attached figure

the solution is the point (-0.22,2.22)

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8. The length of the support is 7. 9 m

9. The length of the conveyer is 12m

3. a = 59m

A = 44°

B = 52°

4. c = 88. 6 mm

b = 49. 1 m

B = 34°

<h3>How to solve the trigonometry</h3>

8. We have the angle to be 20 degrees

Opposite side = x

hypotenuse = 23m

Using the sine ratio

sin θ = opposite/ hypotenuse

sin 20 = \frac{x}{23}

Cross multiply

sin 20 × 23 = x

x = 0. 3420 × 23

x = 7. 9 m

The length of the support is 7. 9 m

9. The angle of elevation is 37. 3 degrees

Hypotenuse = 19 . 0m

Opposite = x

Using the sine ratio

sin θ = opposite/ hypotenuse

sin 37. 3 = \frac{x}{19}

cross multiply

x = 0. 6059 × 19

x = 11.5

x = 12 m in 2 significant figures

The length of the conveyer is 12m

3. To determine the sides and angles, we use the sine rule;

\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}

For side a, we use the Pythagorean theorem

c^2 = a^2 + b^2

85^2 = a^2 + 67^2

a = \sqrt{89^2-67^2}

a = \sqrt{3432}

a = 58. 58, a = 59m

To find angle A and B, use the sine rule

\frac{59}{sin A } = \frac{85}{sin 90}

cross multiply

sin A × 85 = sin 90 × 59

make sin A subject of formula

sin A = \frac{59}{85}

sin A = 0. 6941

A = sin^-^1(0. 6941)

A = 44°

\frac{67}{sin B} = \frac{85}{sin 90}

cross multiply

sin B × 85 = sin 90 × 67

make sin b subject of formula

sin B = \frac{67}{85}

sin B = 0. 7882

B = sin^-^1( 0. 7882)

B = 52°

4. To find the sides, we use the sine rule;

\frac{74. 0}{sin 56. 6} = \frac{c}{sin 90}

Cross multiply

sin 56. 6 × c = sin 90 × 74

make 'c' subject of formula

c = \frac{74}{0. 8348}

c = 88. 6 mm

To find length b, we use the Pythagorean theorem

c^2 = a^2 + b^2

b^2 = c^2 - a^2

b^2 = 88. 8^2 - 74^2

b = \sqrt{7885. 44 - 5476}\\\\ b = \sqrt{2409. 44}

b = 49. 1 m

\frac{74. 0}{sin 56. 6} = \frac{49. 1}{sin B}

cross multiply

sin B = \frac{40. 99}{74. 0}

B = sin^-^1(0. 5539)

B = 34°

Learn more about trigonometric identity here:

brainly.com/question/7331447

#SPJ1

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