Question

Hurry im despret i need help

Answer 1

The slope-point form of line:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (-9, 7) and (6, 2). Substitute:

$m=\dfrac{2-7}{6-(-9)}=\dfrac{-5}{6+9}=-\dfrac{5}{15}=-\dfrac{1}{3}\\\\y-7=-\dfrac{1}{3}(x-(-9))\\\\\boxed{y-7=-\dfrac{1}{3}(x+9)}$

The slope-intercept form of line:

$y=mx+b$.

We have the slope m:

$y=-\dfrac{1}{3}x+b$

Pu the coordinates of the point (6, 2) to the equation:

$2=-\dfrac{1}{3}(6)+b$

$2=-2+b$             add 2 to both sides

$4=b\to b=4$

$\boxed{y=-\dfrac{1}{3}x+4}$