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algol [13]
4 years ago
15

Determine whether The following number sentences are true or false. Justify your answer 6+5=18+5

Mathematics
1 answer:
NemiM [27]4 years ago
3 0

Answer:

5x+1(6-4) = +1(5x6)-(5x)

Step-by-step explanation:

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Plz help i rlly need help . due today
puteri [66]
U divide 4/7 by 3/4 which is 16/21
4 0
3 years ago
Simple geometry please help<br><br> Find KL. Round to the nearest hundredth.
vivado [14]

Answer:

KL ≈ 1.94

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos48° = \frac{adjacent}{hypotenuse} = \frac{JL}{KL} = \frac{1.3}{KL} ( multiply both sides by KL )

KL × cos48° = 1.3 ( divide both sides by cos48° )

KL = \frac{1.3}{cos48} ≈ 1.94 ( to the nearest hundredth )

6 0
3 years ago
PLZ HELP I'm failing​
gizmo_the_mogwai [7]

Answer:

D. 4x+10≥135

Step-by-step explanation:

We know that he has to deliver 10 packages on Friday.

so, 135-10=125

Now, we have Monday to Thursday, thats 4 days.

125/4=32

And, we know that it must be a minimum of 135 packages. So, using this information, we know that the answer has to be D.

Sorry if this was confusing, My mind works in ways that are hard to explain, with math. So, I hope this helps.

8 0
4 years ago
Read 2 more answers
15 - 7 + 3 ( 6 + 2) / 2^3 PLEASE SOLVE BY USING A STEP BY STEP SOLUTION
Slav-nsk [51]

Answer:

<h2>11</h2>

Step-by-step explanation:

PEMDAS

Parentheses first:

15 - 7 + 3 (8) / 2^3

Exponent second:

15 - 7 + 3 (8) / 8

Multiplication:

15 - 7 + 24 / 8

Division:

15 - 7 + 3

Addition:

15 - 4

Subtraction:

11

6 0
3 years ago
What is the solution, if any, to the inequality 3-14-n1 &gt; 1?
mezya [45]

Answer:

n > 2 or n < 6

Step-by-step explanation:

3 - | 4 - n | < 1

Let's move 3 to the other side of the equation:

- | 4 - n | < 1 - 3

- | 4 - n | < -2

Both sides of the equation are negative, so we can simplify by multiplying them with -1:

(- | 4 - n | < -2*-1

| 4 - n | < 2

We cannot get rid of the module because it's not for a single number and we dont know what n is equal to but there is a rule that we can use to remove the module:

- if | x | < a and a > 0 then -a < x < a. So if we use it we get the following:

- 2 < 4 - n < 2

These are two equations, separate and solve them separately

4 - n < 2

- n < 2 - 4

- n < -2

n > 2 (< turns into > because we changed sign)

and

- 2 < 4 - n

4 - n > -2

-n > -2 - 4

n < 6 (we change the sign of the numbers so the equation changes too)

So after solving the two equation we get the answers

8 0
3 years ago
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