Answer:
Option d is the correct answer for the above question.
Explanation:
- WAN is a type of network that facilities network connection all over the world. It can connect every computer which is in anywhere in the world while the other technology like LAN and MAN is used for small area locations.
- The above question asked that about that statement which is not the property of WAN and that is option d because it states that WAN is used to connect only small areas of computers, but it can connect all the computers of the world, while the other property is valid for WAN.
Answer:
embedded system
Explanation:
Based on the scenario being described within the question it can be said that the type of software that is being described is known as an embedded system. This is actually a combination of both hardware and software that focuses on a specific function which is later implemented into a much larger system to allow it to become "smarter", by performing more complex tasks, which would otherwise not be possible.
Answer:
A. Run the parted command.
D. Reboot the system.
Explanation:
Linux command line shell is a vital tooling server administration. It provides the flexibility of executing user and kernel mode commands on the command line interface.
Unlike graphic user interface operating systems, it receives typed commands on its prompt to execute tasks. The fdisk command shows the newly created partition on a disk, and to reload, the parted command is executed or the system should be rebooted.
<u>Explanation:</u>
Hey there! you need not to panic about it ,your program didn't have Driver program i.e main program! the correct & working code is given below:
// C++ program to count even digits in a given number .
#include <iostream>
using namespace std;
// Function to count digits
int countEven(int n)
{
int even_count = 0;
while (n > 0)
{
int rem = n % 10;
if (rem % 2 == 0)
even_count++;
n = n / 10;
}
cout << "Even count : "
<< even_count;
if (even_count % 2 == 0 )
return 1;
else
return 0;
}
// Driver Code
int main()
{
int n;
std::cin >>n;
int t = countEven(n);
return 0;
}
