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shepuryov [24]
2 years ago
13

Hi! I'm Kayla! I was wondering who does homework on the weekends... anybody?? I guess almost everyone, including me. Anyways, le

t me know! Either way, have a great day!!!
P.s. question does not relate to subject. thx :)
Computers and Technology
2 answers:
Dovator [93]2 years ago
7 0

I do my homework on Friday if I can, I like to have my weekends free to do whatever I want :)

Goshia [24]2 years ago
6 0
I’m homeschooled and when I’m doing homework (plus when I was at public school, I did this) I usually do my work early in the weekend (Friday and/or Saturday) so that I’ll have about a day or two of free time before going back to school.
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Which of the following is not a property of a WAN:
docker41 [41]

Answer:

Option d is the correct answer for the above question.

Explanation:

  • WAN is a type of network that facilities network connection all over the world. It can connect every computer which is in anywhere in the world while the other technology like LAN and MAN is used for small area locations.
  • The above question asked that about that statement which is not the property of WAN and that is option d because it states that WAN is used to connect only small areas of computers, but it can connect all the computers of the world, while the other property is valid for WAN.
6 0
3 years ago
Software (often on firmware) designed to make physical products and devices "smarter" by doing things like sharing usage informa
kolezko [41]

Answer:

embedded system

Explanation:

Based on the scenario being described within the question it can be said that the type of software that is being described is known as an embedded system. This is actually a combination of both hardware and software that focuses on a specific function which is later implemented into a much larger system to allow it to become "smarter", by performing more complex tasks, which would otherwise not be possible.

5 0
3 years ago
Aria has modified the hard disk that hosts the operating system by using the fdisk command. The fdisk command indicates that the
Neko [114]

Answer:

A. Run the parted command.

D. Reboot the system.

Explanation:

Linux command line shell is a vital tooling server administration. It provides the flexibility of executing user and kernel mode commands on the command line interface.

Unlike graphic user interface operating systems, it receives typed commands on its prompt to execute tasks. The fdisk command shows the newly created partition on a disk, and to reload, the parted command is executed or the system should be rebooted.

3 0
3 years ago
An access control system that grants users only those rights necessary for them to perform their work is operating on which secu
solmaris [256]

Answer:

B. Least privilege                

Explanation:

  • The principle of least privilege an important principle in computer security.
  • It limits the access rights for users and only grant them with the rights that are sufficient for them to perform their required task.
  • For example a user is granted privilege to execute a file or manipulate data or use only the resources that are required for them to perform a particular task.
  • This principle can be used only to limit and control access rights to system resources and applications.
  • The least privilege is beneficial as it reduces the risk of unauthorized access.
  • For example a user whose task is data entry and has nothing to do with controlling access or granting access rights to users, will only be allowed to enter data to the DB by the principle of least privilege.
7 0
3 years ago
URGENT!
lutik1710 [3]

<u>Explanation:</u>

Hey there! you need not to panic about it ,your program didn't have Driver program i.e main program! the correct & working code is given below:

// C++ program to count  even digits  in a given number .

#include <iostream>  

using namespace std;  

// Function to count digits

int countEven(int n)  

{  

int even_count = 0;    

while (n > 0)  

{  

 int rem = n % 10;  

 if (rem % 2 == 0)  

  even_count++;  

 n = n / 10;  

}  

cout << "Even count : "

 << even_count;  

if (even_count % 2 == 0 )  

 return 1;  

else

 return 0;  

}  

// Driver Code  

int main()  

{  

int n;  

std::cin >>n;

int t = countEven(n);  

return 0;  

}  

6 0
2 years ago
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