Answer:
no they are not
Step-by-step explanation:
Answer: 271
Step-by-step explanation:
The formula we use to find the sample size is given by :-
, where is the two-tailed z-value for significance level of
p = prior estimation of the proportion
E = Margin of error.
If prior estimation of the proportion is unknown, then we take p= 0.5 , the formula becomes
Given : Margin of error : E= 0.05
Confidence level = 90%
Significance level
Using z-value table , Two-tailed z-value for significance level of
Then, the required sample size would be :
Simplify,
Hence, the required minimum sample size =271
You mean common factors ?
1,2,5,10
Answer:
5
Step-by-step explanation:
If you draw a rectangle, the lenght is 6. So both sides should be 6.
6+6=12.
22-12= 10.
10 divided by 2 is equal to 5.
<h2>5 is the answer.</h2>
Answer:
The Estimate the number of students who took the scores between 82 and 98 = 16
Step-by-step explanation:
<u><em>Explanation</em></u>:-
Given data The scores on a math test are normally distributed with a mean μ = 74
standard deviation of Population
S.D (σ) = 8
Let 'x' be the random variable of Normal distribution
<u><em>case(i)</em></u>:- when x = 82
<u><em>case(ii)</em></u>:- when x = 98
The probability that test scores between 82 and 98.
P(82≤x≤98) = P(1≤z≤3)
= P(z≤3) - P(z≤1)
= 0.5+A(3)-(0.5+A(1))
= A(3) -A(1)
= 0.4986 - 0.3413
= 0.1573
<u><em>Final answer</em></u>:-
The Estimate the number of students who took the scores between 82 and 98
= 100 X 0.1573 = 15.73 ≅16