Answer: you're gonna need to tell us the measurements of the triangle or else we can't help you find the area
I would say that it is either <span>B. Multiply the second equation by 4. Then add that result to the first equation or </span><span>D. Add the two equations together </span>
It’s the second one, 65.4
V=1
6πd3=1
6·π·53≈ 65.44985in³
The <em>second order</em> polynomial that involves the variable <em>x</em> (border inside the rectangle) and associated to the <em>unshaded</em> area is x² - 62 · x + 232 = 0.
<h3>How to derive an expression for the area of an unshaded region of a rectangle</h3>
The area of a rectangle (<em>A</em>), in square inches, is equal to the product of its width (<em>w</em>), in inches, and its height (<em>h</em>), in inches. According to the figure, we have two <em>proportional</em> rectangles and we need to derive an expression that describes the value of the <em>unshaded</em> area.
If we know that <em>A =</em> 648 in², <em>w =</em> 22 - x and <em>h =</em> 40 - x, then the expression is derived below:
<em>A = w · h</em>
(22 - x) · (40 - x) = 648
40 · (22 - x) - x · (22 - x) = 648
880 - 40 · x - 22 · x + x² = 648
x² - 62 · x + 232 = 0
The <em>second order</em> polynomial that involves the variable <em>x</em> (border inside the rectangle) and associated to the <em>unshaded</em> area is x² - 62 · x + 232 = 0. 
To learn more on polynomials, we kindly invite to check this verified question: brainly.com/question/11536910
Answer:
See step-by-step explanation
Step-by-step explanation:
16. C, <AOB = 20
The total angle (<AOC) is equal to the sum of the angles inside of it (<AOB and < BOC).
<AOC= <AOB + <BOC
47=<AOB+27
<AOB=20
17. 24
Area of a square = 
36= 
s= 6
One side is 6
The perimeter of a square is 4(s)
4(6) = 24
Word of encouragement:
Good luck!