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3 years ago

HELP PLZ PLZ Why should you use the median and interquartile range (IQR) to compare two populations that contain outliers?

Mathematics

1 answer:

Zielflug [23.3K]3 years ago

3 0

Answer: The median and IQR are not influenced by the presence of outliers.

Step-by-step explanation: The median and IQR will not change with ouliers but something like mean would so if there is outliers you should use median to properly represent the numbers

hope this helps mark me brainliest if you can

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Given:• PQRS is a rectangle.• mZ1 = 50°Р21SRWhat is mZ2?130°85°70°65°

Over [174]

To answer this question, we need to recall that: "the diagonals of a rectangle bisect each other"

Thus, if we assign the point of intersection of the two diagonals in the rectangle as point O, we can say that the triangle OQR is an "isosceles triangle". Note that this is because the lengths OR and OQ are equal since we know that: "the diagonals of a rectangle bisect each other". See the below diagram for clarity.

Now, we have to recall that:

- the base angles of any isosceles triangle are equal. This is a fact, and this means that the angles

- also the sum of all the angles in any triangle is 180 degrees

Now, considering the isosceles triangle OQR, we have that:

$\angle OQR+\angle ORQ+\angle ROQ=180^o$

Now, since the figure already shows that angle $m\angle2+\angle ORQ+50^o=180^o$ Now, since we have established that the base angles $m\angle2+m\angle2+50^o=180^o$ we can now solve the above equation for m<2 as follows:

$\begin{gathered} m\angle2+m\angle2+50^o=180^o \\ \Rightarrow2m\angle2+50^o=180^o \\ \Rightarrow2m\angle2=180^o-50^o \\ \Rightarrow2m\angle2=130^o \\ \Rightarrow m\angle2=\frac{130^o}{2}=65^o \end{gathered}$

Therefore, the correct answer is: option D

7 0

1 year ago

8. A computer application generates a sequence of musical notes using the function f(n) 6(16)", where n is the

s2008m [1.1K]

Applying an exponential property, it is found that the function that will generate the same note sequence as function f(n) is given by:

B. $H(n) = 6(2)^{4n}$

<h3>What is function for the note sequence?</h3>

The function for the node sequence is defined by:

$f(n) = 6(16)^n$

A function that will the same note sequence as function f(n) has the same initial value of 6. Additionally, applying an exponential property, we have that:

$H(n) = 6(2)^{4n} = 6(2^4)^n = 6(16)^n$

Hence option B is correct.

More can be learned about exponential properties at brainly.com/question/25537936

#SPJ1

3 0

2 years ago

I’m actually so dumb!!!<br> How???<br> Answer???

Pani-rosa [81]

Standard form: 2x - 16 = 0

Factorization: 2(x - 8) = 0

Solutions: x = 16/2 = 8

Hope this helps!

6 0

3 years ago

Read 2 more answers

What is the volume of the composite figure? Explain your work. A complete answer should include how you broke up the figure, whi

Sphinxa [80]

Answer:

$15,000\:\mathrm{mm^3}$

Step-by-step explanation:

The composite figure consists of a square prism and a trapezoidal prism. By adding the volume of each, we obtain the volume of the composite figure.

The volume of the square prism is given by $V=s^2\cdot h$ , where $s$ is the base length and $h$ is the height. Substituting given values, we have: $V=14^2\cdot 30=196\cdot 30=5,880\:\mathrm{mm^3}$

The volume of a trapezoidal prism is given by $V=\frac{b_1+b_2}{2}\cdot l\cdot h$ , where $b_1$ and $b_2$ are bases of the trapezoid, $l$ is the length of the height of the trapezoid and $h$ is the height. This may look very confusing, but to break it down, we're finding the area of the trapezoid (base) and multiplying it by the height. The area of a trapezoid is given by the average of the bases ( $\frac{b_1+b_2}{2}$ ) multiplied by the trapezoid's height ( $l$ ).