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11Alexandr11 [23.1K]
3 years ago
10

HELP PLZ PLZ Why should you use the median and interquartile range (IQR) to compare two populations that contain outliers?

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
3 0

Answer: The median and IQR are not influenced by the presence of outliers.

Step-by-step explanation: The median and IQR will not change with ouliers but something like mean would so if there is outliers you should use median to properly represent the numbers

hope this helps mark me brainliest if you can

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Solve rational inequality x²+x-6/x²-3x-4≤0?​
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Answer:

Step-by-step explanation:

x

2

+

x

−

6

=

(

x

+

3

)

(

x

−

2

)

x

2

−

3

x

−

4

=

(

x

−

4

)

(

x

+

1

)

Each of the linear factors occurs precisely once, so the sign of the given rational expression will change at each of the points where one of the linear factors is zero. That is at:

x

=

−

3

,

−

1

,

2

,

4

Note that when

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is large, the

x

2

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Hence the sign of the value of the rational expression in each of the intervals

(

−

∞

,

−

3

)

,

(

−

3

,

−

1

)

,

(

−

1

,

2

)

,

(

2

,

4

)

and

(

4

,

∞

)

follows the pattern

+

−

+

−

+

. Hence the intervals

(

−

3

,

−

1

)

and

(

2

,

4

)

are both part of the solution set.

When

x

=

−

1

or

x

=

4

, the denominator is zero so the rational expression is undefined. Since the numerator is non-zero at those values, the function will have vertical asymptotes at those points (and not satisfy the inequality).

When

x

=

−

3

or

x

=

2

, the numerator is zero and the denominator is non-zero. So the function will be zero and satisfy the inequality at those points.

Hence the solution is:

x

∈

[

−

3

,

−

1

)

∪

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2

,

4

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