All categories

3 years ago

What are the coordinets?

Mathematics

1 answer:

liraira [26]3 years ago

3 0

Answer:

numbers that are plotted on a graph

Step-by-step explanation:

examples:

(2,8) this is a coordinate

(4,16)

(5,25)

You might be interested in

What is m X to the nearest degree? Help plssss

aalyn [17]

Answer:

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos X = $\frac{adjacent}{hypotenuse}$ = $\frac{XY}{XZ}$ = $\frac{13}{18}$ , then

∠ X = $cos^{-1}$ ( $\frac{13}{18}$ ) ≈ 44° ( to the nearest degree ) → A

5 0

3 years ago

Read 2 more answers

Convert 41 degrees Fahrenheit to degrees Celsius

Fittoniya [83]

Answer:

Step-by-step explanation:

41-32=9

9 × 5/9=5

so it's 5

5 0

3 years ago

Read 2 more answers

The length of a rectangular field is 4 m longer than its width.

Artyom0805 [142]

We know the perimeter is the sum of all sides. So lenght+length+width+width = 2length+2width.
Let's call the width x. If the length is 4m longer, then it's x+4.
We know the perimeter, so we can make an equation:
56=2x+2(x+4)
And solve from there:
56=2x+2x+8
56=4x+8
48=4x
48/4=x
x=12

The width, which is x, is 12 m. And the length, x+4, is 16 m.
You can check this is correct by calculating the perimeter using those values: 12+12+16+16=56.

7 0

3 years ago

2.1x10^6 ______ 7x10^3 answer in standard form ...................10^......

VMariaS [17]

Given:

The expression is:

$\dfrac{2.1\times 10^6}{7\times 10^3}$

To find:

The simplified form of the given expression in standard form.

Solution:

We have,

$\dfrac{2.1\times 10^6}{7\times 10^3}$

It can be written as:

$\dfrac{2.1\times 10^6}{7\times 10^3}=\dfrac{21\times 10^5}{7\times 10^3}$

$\dfrac{2.1\times 10^6}{7\times 10^3}=\dfrac{21}{7}\times \dfrac{10^5}{10^3}$

$\dfrac{2.1\times 10^6}{7\times 10^3}=3\times 10^{5-3}$ $[\because \dfrac{a^m}{a^n}=a^{m-n}]$

$\dfrac{2.1\times 10^6}{7\times 10^3}=3\times 10^2$

Therefore, the required value is $3\times 10^2$ .

4 0

3 years ago

Each side of a square is increasing at a rate of 2 cm/s. at what rate is the area of the square increasing when the area of the

faltersainse [42]

Let x(t) = the length of a side of the square (cm) at time t (s).
The rate of change of x is given as
$\frac{dx}{dt} =2 \, \frac{cm}{s}$

The area (cm²) at time t is
A = x²

The rate of change of the area with respect to time is
$\frac{dA}{dt} = \frac{dA}{dx} \frac{dx}{dt} =2 \frac{dA}{dx} =2(2x)=4x \, \frac{cm^{2}}{s}$

When A = 9 cm², then x = √9 = 3cm. Hence obtain
$\frac{dA}{dt} = 4(3) = 12 \, \frac{cm^{2}}{s}$

Answer: 12 cm²/s

3 0

3 years ago