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sergeinik [125]
3 years ago
10

my question is 2x^2+13x+6=0 HOW???? there are no numbers that multiply to 6 and can add to 13. Please help I'm so confused!!!

Mathematics
1 answer:
kondor19780726 [428]3 years ago
7 0
Look

2x^2+13x+6
factored into
(ax+b)(cx+d)
we need to find a,b,c,d such that when multipied we get 2x^2+13x+6
first
we know that the first number hast to be 2
(2x+somethin)(1x+sometin)
and the end numbers have to multiply to 6
if we try 1 and 6
(2x+1)(x+6)=
2x^2+x+12x+6=
2x^2+13x+6
correct

so
2x^2+13x+6=0=(2x+1)(x+6)

therefor assume
2x+1=0 and x+6=0

2x+1=0
minus 1
2x=-1
divide 2
x=-1/2

other one
x+6=0
mnus 6
x=-6

x=-6 or -1/2


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Answer:

Step-by-step explanation:

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Let the time taken by the john to get back from his uncle be y.

So,

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gogolik [260]

Using it's concept, the standard deviation for the given data-set is of 8.22.

<h3>What are the mean and the standard deviation of a data-set?</h3>

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The mean for this problem is:

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Hence the standard deviation is:

S = \sqrt{\frac{(17-21)^2 + (26-21)^2 + (28-21)^2 + \cdots + (21-21)^2 + (23-21)^2}{9}} = 8.22

More can be learned about the standard deviation of a data-set at brainly.com/question/12180602

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2 years ago
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larisa [96]
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7 0
3 years ago
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Answer:

$5.65

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5.65

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