2x^2+13x+6 factored into (ax+b)(cx+d) we need to find a,b,c,d such that when multipied we get 2x^2+13x+6 first we know that the first number hast to be 2 (2x+somethin)(1x+sometin) and the end numbers have to multiply to 6 if we try 1 and 6 (2x+1)(x+6)= 2x^2+x+12x+6= 2x^2+13x+6 correct
