So the image below shows what quadrants are. From the top-right square, the order of quadrants goes from 1-4 in a counter-clockwise matter.
Quadrant I: Top-right square
Quadrant II: Top-left square
Quadrant III: Bottom-left square
Quadrant IV: Bottom-right square.
Any points that are on the bolded vertical line are on the y-axis, and any points on the bolded horizontal line is on the x-axis.
Y=mx+b
m=0.5
b is value of y in y-intercept, b=-2
The equation of this line is
y=0.5x-2
When x=4
y=0.5x-2=y=0.5*4-2=2-2 = 0
When x=4, y=0.
Answer:
1/4= 25%
Step-by-step explanation:
Wow !
OK. The line-up on the bench has two "zones" ...
-- One zone, consisting of exactly two people, the teacher and the difficult student.
Their identities don't change, and their arrangement doesn't change.
-- The other zone, consisting of the other 9 students.
They can line up in any possible way.
How many ways can you line up 9 students ?
The first one can be any one of 9. For each of these . . .
The second one can be any one of the remaining 8. For each of these . . .
The third one can be any one of the remaining 7. For each of these . . .
The fourth one can be any one of the remaining 6. For each of these . . .
The fifth one can be any one of the remaining 5. For each of these . . .
The sixth one can be any one of the remaining 4. For each of these . . .
The seventh one can be any one of the remaining 3. For each of these . . .
The eighth one can be either of the remaining 2. For each of these . . .
The ninth one must be the only one remaining student.
The total number of possible line-ups is
(9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1) = 9! = 362,880 .
But wait ! We're not done yet !
For each possible line-up, the teacher and the difficult student can sit
-- On the left end,
-- Between the 1st and 2nd students in the lineup,
-- Between the 2nd and 3rd students in the lineup,
-- Between the 3rd and 4th students in the lineup,
-- Between the 4th and 5th students in the lineup,
-- Between the 5th and 6th students in the lineup,
-- Between the 6th and 7th students in the lineup,
-- Between the 7th and 8th students in the lineup,
-- Between the 8th and 9th students in the lineup,
-- On the right end.
That's 10 different places to put the teacher and the difficult student,
in EACH possible line-up of the other 9 .
So the total total number of ways to do this is
(362,880) x (10) = 3,628,800 ways.
If they sit a different way at every game, the class can see a bunch of games
without duplicating their seating arrangement !
Hello from MrBillDoesMath!
Answer: The domain is the set of real numbers.
the full real number system
Discussion:
f(x) = (4/5)^x is defined for all x as the underlying function (4/5)^x is defined for all x. Therefore the domain is the set of real numbers.
Thank you,
MrB
