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steposvetlana [31]
3 years ago
9

Help me solve using either elimination or comparison.

Mathematics
1 answer:
Nadya [2.5K]3 years ago
8 0
I hope this helps you

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A single​ 6-sided die is rolled twice. The set of 36 equally likely outcomes is​ {(1,1), (1,2),​ (1,3), (1,4), left parenthesis
Dennis_Churaev [7]

Answer:

The probability of getting two numbers whose sum is greater than 9 and less than 13 is \frac{1}{6}

Step-by-step explanation:

Given : A single​ 6-sided die is rolled twice.

To find : The probability of getting two numbers whose sum is greater than 9 and less than 13 ?

Solution :

The set of 36 equally likely outcomes,

          1              2              3              4               5             6

1 (1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

2 (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

3 (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

4 (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

5 (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

6 (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

Getting two numbers whose sum is greater than 9 and less than 13

The favorable outcome is (4,6),(5,5),(5,6),(6, 4),(6, 5),(6, 6) = 6

The probability is given by,

\text{Probability}=\frac{\text{Favorable Outcome}}{\text{Total Outcome}}

\text{Probability}=\frac{6}{36}

\text{Probability}=\frac{1}{6}

Therefore, The probability of getting two numbers whose sum is greater than 9 and less than 13 is \frac{1}{6}

5 0
3 years ago
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