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3 years ago

10

A shirt originally cost $54.01, but it is on sale for $37.81. What is the percentage decrease of the price of the shirt? If nece

ssary, round to the nearest percent
A. 24%
B. 43%
C. 30%
D. 70%

1 answer:

Marianna [84]3 years ago

3 0

I think it's rounds at to 30

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Last question I swear

kirza4 [7]

Answer:

y = 3

Step-by-step explanation:

Subtract 11 from both sides to get:

2y = 6

Then divide both sides by 2 to isolate y:

y = 3

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3 years ago

The angle of elevation to the top of a skyscraper is measured to be 2 degrees from a point on the ground 1 mile from the buildin

Alex

Answer:

0.034921 miles or 1843774 feet tall

Step-by-step explanation:

Using trigonometric functions we know that $x=rcos(\theta)$ and $y=rsin(\theta)$ where $\theta$ =angle and r is the hypotenuse of the triangle.

First we will calculate the hypotenuse using the x equation, since we know x = 1 mile (distance from the building on the ground) we have:

$x=rcos(\theta)\\\\1=rcos(2)\\\\r=\frac{1}{cos(2)} \approx. 1.0061mi$

Now we will calculate the height of the building using the y equation and so:

$y=rsin(\theta)\\\\y=\frac{1}{cos(2)} \times sin(2) = \frac{sin(2)}{cos(2)}=tan(2)=0.034921mi$

The building is 0.034921 miles or approximately 184.3774 feet tall.

4 0

3 years ago

1. 6 times a number is 30, what is the number?

statuscvo [17]

5 for the first one and 7 for the second hope this helps

6 0

3 years ago

The center of a circle is at the origin. and endpoint of a diameter of the circle is at (-3, -4. how long is the diameter of the

Aleks [24]

The diameter is 10:

To do this we must use the distance formula:

Distance =√(x2−x1)^2+(y2−y1)^2

So, if we substitute in our values for the origin and endpoint (origin is 1 values, endpoint is 2)

D=✓(-4-0)^2+(-3-0)^2

Simplified, this is

D=✓16+9
D=✓25
D=5

so, the distance from the center of the crcle to the endpoint is 5 (making the radius)

multiply by two, and the diameter of the circle is 10 :)

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3 years ago

For each of the following vector fields

olga nikolaevna [1]

(A)

$\dfrac{\partial f}{\partial x}=-16x+2y$

$\implies f(x,y)=-8x^2+2xy+g(y)$

$\implies\dfrac{\partial f}{\partial y}=2x+\dfrac{\mathrm dg}{\mathrm dy}=2x+10y$

$\implies\dfrac{\mathrm dg}{\mathrm dy}=10y$

$\implies g(y)=5y^2+C$

$\implies f(x,y)=\boxed{-8x^2+2xy+5y^2+C}$

(B)

$\dfrac{\partial f}{\partial x}=-8y$

$\implies f(x,y)=-8xy+g(y)$

$\implies\dfrac{\partial f}{\partial y}=-8x+\dfrac{\mathrm dg}{\mathrm dy}=-7x$

$\implies \dfrac{\mathrm dg}{\mathrm dy}=x$

But we assume $g(y)$ is a function of $y$ alone, so there is not potential function here.

(C)

$\dfrac{\partial f}{\partial x}=-8\sin y$

$\implies f(x,y)=-8x\sin y+g(x,y)$

$\implies\dfrac{\partial f}{\partial y}=-8x\cos y+\dfrac{\mathrm dg}{\mathrm dy}=4y-8x\cos y$

$\implies\dfrac{\mathrm dg}{\mathrm dy}=4y$

$\implies g(y)=2y^2+C$

$\implies f(x,y)=\boxed{-8x\sin y+2y^2+C}$

For (A) and (C), we have $f(0,0)=0$ , which makes $C=0$ for both.

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3 years ago