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PtichkaEL [24]
3 years ago
13

What is the constant proportionality for y=2/3x

Mathematics
2 answers:
saul85 [17]3 years ago
5 0

Answer:

\text{The proportionality constant is }\frac{2}{3}

Step-by-step explanation:

we have to find the constant proportionality for

y=\frac{2}{3}x

Given two variables x and y, y is directly proportional to x if there is a non-zero constant k such that

y ∝ x

⇒ y=kx   →  (1)

Here, k is known as constant proportionality.

Now, y=\frac{2}{3}x   →   (2)

Comparing (1) and (2), we get

k=\frac{2}{3}

\text{The proportionality constant is }\frac{2}{3}

Lerok [7]3 years ago
3 0
The constant proportionality is 2/3 because it will still be going on
for example- 2/3+2/3= 2/3*2

The number 2/3 goes 
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A standard weight known to weigh 10 grams. Some suspect bias in weights due to manufacturing process. To assess the accuracy of
notsponge [240]

Answer:

a) The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams

b) 49 measurements are needed.

Step-by-step explanation:

Question a:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.98}{2} = 0.01

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

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Now, find the margin of error M as such

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The upper end of the interval is the sample mean added to M. So it is 10 + 0.00031 = 10.00471 grams

The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams.

(b) How many measurements must be averaged to get a margin of error of +/- 0.0001 with 98% confidence?

We have to find n for which M = 0.0001. So

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0.0001\sqrt{n} = 2.327*0.0003

\sqrt{n} = \frac{2.327*0.0003}{0.0001}

(\sqrt{n})^2 = (\frac{2.327*0.0003}{0.0001})^2

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Rounding up

49 measurements are needed.

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Answer:

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