The y-intercept of the trend line is (0,28). The slope of this line is
28-0
m = --------- = 2
14-0
Thus, the equation of the trend line, in variables K and J, is
K = 2J + 28
If you have a calculator with statistical functions, that's the way to go.
On my TI-83, I typed in invNorm(0.88) and got the result z = 1.17.
88% of the area under the normal curve is to the left of z = 1.17.
Answer:
20 yd^2
Step-by-step explanation:
Your work is partially correct.
Assuming that the sides marked 8 yds and 2 yds are parallel, then the area of the trapezoid is
A = ( 8 yds + 2 yds)
------------------------ * 4 = 20 yd^2
2
