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Gala2k [10]
3 years ago
13

Demi loves playing online games. She surfs through many websites to find new, interesting games. One day she finds that her mail

box is filled with emails suggesting websites for online games and ads promoting a few online offers. In this scenario, a(n) _____ tracks Demi's computer behavior to send her targeted mails and ads.
A. Firewall
B. Spyware
C. Bastion host
D. Attack tree
Computers and Technology
1 answer:
Marianna [84]3 years ago
4 0

Answer:

Option (B) is the correct answer.

Explanation:

The following terms are as follows:

Firewall: Firewall can be described as a security system for a network, which is used to check the incoming and outgoing data on the network on the basis of rules determined by the system.

Spyware: Spyware defines as a program that can record your activity secretly and then use it for many purposes i.e advertisements, promotions, and many other legal and illegal purposes.

Bastion host: Bastion host mainly used to access the private network from any other network.

Attack trees: Attack trees are used to examine the security of any system against any attacks.

According to the scenario, the most appropriate answer is option (B) because spywares are also used for promotion.

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The SNMP agent on a router authenticates any SNMP Get requests received from the NMS using either the read-write or read-only community string.

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We have said that the average number of comparisons need to find a target value in an n-element list using sequential search is
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Answer:

Part a: If the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b: If the list contains n elements (where n is even) the middle terms are  at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c: The average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

Explanation:

Suppose the list is such that the starting index is 0.

Part a

If list has 15 elements, the middle item would be given at 7th index i.e.

there are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(8,9,10,11,12,13,14) above it. It will have to run 8 comparisons  to find the middle term.

If list has 17 elements, the middle item would be given at 8th index i.e.

there are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(9,10,11,12,13,14,15,16) above it.It will have to run 9 comparisons  to find the middle term.

If list has 21 elements, the middle item would be given at 10th index i.e.

there are 10 indices (0,1,2,3,4,5,6,7,8,9) below it and 10 indices (11,12,13,14,15,16,17,18,19,20) above it.It will have to run 11 comparisons  to find the middle term.

Now this indicates that if the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b

If list has 16 elements, there are two middle terms as  one at would be at 7th index and the one at 8th index .There are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(9,10,11,12,13,14,15) above it. It will have to run 9 comparisons  to find the middle terms.

If list has 18 elements, there are two middle terms as  one at would be at 8th index and the one at 9th index .There are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(10,11,12,13,14,15,16,17) above it. It will have to run 10 comparisons  to find the middle terms.

If list has 20 elements, there are two middle terms as  one at would be at 9th index and the one at 10th index .There are 9 indices(0,1,2,3,4,5,6,7,8) below it and 9 indices(11,12,13,14,15,16,17,18,19) above it. It will have to run 11 comparisons  to find the middle terms.

Now this indicates that if the list contains n elements (where n is even) the middle terms are  at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c

So the average number of comparisons is given as

((n+1)/2+(n+2)/2)/2=(2n+3)/4

So the average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

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