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Cerrena [4.2K]
4 years ago
10

Need an answer for this pls its mult choice

Mathematics
2 answers:
defon4 years ago
8 0

Answer:d

Step-by-step explanation:

tensa zangetsu [6.8K]4 years ago
5 0

These are special triangles. The triangle with a hypotenuse of 11 is a 30-60-90 triangle, and the other triangle in the diagram is a 45-45-90 triangle. For such triangles, the following properties apply.

For 30-60-90 triangles:

If the short leg is x -

· the hypotenuse is 2x

· the long leg is x√(3)

For 45-45-90 triangles:

Their legs are congruent. If their legs are x -

· the hypotenuse is x√(2)

We can find x by determining the length of the legs of the 45-45-90 triangle and using the above property. Notice that one of the legs of the 45-45-90 triangle is also the long leg of the 30-60-90 triangle. By finding the length of the long leg of the 30-60-90 we can determine the length of the hypotenuse of the 45-45-90 triangle.

The hypotenuse measures 11. The long leg is √(3) times the length of the short leg. The short leg is half the hypotenuse, thus the short leg is 5.5. The long leg is 5.5√(3) or \frac{11\sqrt{3}}{2}. Since this is the length of the legs of the 45-45-90 triangle, the hypotenuse (x) is \frac{11\sqrt{3}}{2} \cdot\sqrt{2}.

\frac{11\sqrt{3}}{2} \cdot\sqrt{2}

Simplify.

\frac{11\sqrt{3}\sqrt{2}}{2}

\frac{11\sqrt{6}}{2}

Answer:

D. \frac{11\sqrt{6}}{2}

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