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3 years ago

2b^2 +32b + 128 Pls answer this

Mathematics

2 answers:

KengaRu [80]3 years ago

8 0

Answer:

${2b}^{2} + 32b + 128$

Factor and get

$x = - 8$

yulyashka [42]3 years ago

5 0

X = -8
When expanding you get -8

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4 years ago

Simplify this equation Thanks a lot!!!

den301095 [7]

Answer:

-1

Step-by-step explanation:

We need to simplify the given expression . The given expression is ,

$\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}$

Here we can see that the power of the both exponent is same that is (2n+1) . Recall the property of exponents ,

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This can be written as ,

$\rm\implies\{( 2 \sqrt6 +5) ( 2\sqrt6 - 5)\}^{2n-1}$

Simplifying using ( a+b)(a-b) = a² - b² ,

$\rm\implies\{( 2 \sqrt6)^2 -5^2 \}^{2n-1}\\\\\rm\implies ( 24 - 25)^{2n-1}$

Subtracting the numbers inside the brackets ,

$\rm\implies (-1)^{2n - 1 }$

Now we know that every odd number is in the form of 2n -1 , where n is any integer. Therefore , the power is odd .

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$\rm\implies\boxed{\quad \red{ -1 }\quad }$

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3 years ago

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