Answer:
if you dont know me neither so sorry tho
Explanation:
The easiest way to find such limits, where there is a numerator and a denominator is to apply <span><span>Hospital's Rule.
1st find the derivative of the numerator and the derivative of the denominator, if it still gives an indeterminate value, find the second derivative of N and D
3) lim sin(2x)/x when x →0
Derivative sin2x → 2cos2x
Derivative x→ 1
2cos2x/1 when x→0 , 2cos2x → 2
and lim sin(2x)/x when x →0 is 2
4) lim(sinx)/(2x²-x)
→cosx/(2x-1) when x →0 cosx/(2x-1) = -1
and lim(sinx)/(2x²-x) when x →0 is -1
and so on and so forth. Try to continue following the same principle
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