Question

if f(x)=2(x)^2+5sqrt(x+2), complete the follwoing statement ( round your answer to the nearest hundreth) : f(0)=_____

Answer 1

Answer:

$f(0)=7.07$

Step-by-step explanation:

We have the function $f(x)=2(x)^2+5\sqrt{(x+2)}$

In this case we want to find the value of f0)

To find f(0) you must replace the x in the function with the number 0 and solve as shown below

$f(0)=2(0)^2+5\sqrt{(0+2)}$

$f(0)=0+5\sqrt{(0+2)}$

$f(0)=5\sqrt{(2)}$

Therefore

$f(0)=7.07$