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Citrus2011 [14]
3 years ago
15

What’s the product (5r+2)(3r-4)

Mathematics
2 answers:
WINSTONCH [101]3 years ago
8 0
   5r + 2 
x 3r  - 4
------------
              -20r -8
15r^2      6r
------------------------
15r^2    + 14r -8 
Marrrta [24]3 years ago
3 0
(5r+2)(3r-4) =15r^2-20r+6r-8=15r^2-14r-8
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Solve |5x+30|=10x ......
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Answer:

Option A

Step-by-step explanation:

We need to solve out ,

\implies |5x + 30| = 10x

We can write it as ,

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On simplyfing further,

\implies 5x + 30 =  10x \quad or \quad 5x +30=-10x

On solving the above equation , we will get ,

\implies \boxed{ x = 6,-2}

Now we know that the value of modulus is never negative so when we will put x is equal to 2 on the RHS we will get -20 which is not possible . Therefore , the extraneous root is -2 .

<u>Option</u><u> </u><u>A </u><u>is </u><u>correct</u><u> </u><u>.</u>

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3 years ago
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Aleksandr [31]

Answer:

D ($46.19)

Step-by-step explanation:

$124.85 * (100% - 63%)

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Hope this helped!

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4 years ago
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Who knows how you do you this??
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Hi!
Okay, so this actually isn't too bad! (For number 5) Just add the negative x over to get 2x. Then subtract 2 over to get -10. Then divide by 2 (-5) and you're done! For the rest, do the same thing. Get the x's on one side, get the regular numbers on the other, and divide! Hope that helped!
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Step-by-step explanation:

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