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2 years ago

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One-fifth of the sum of q and 4

1 answer:

pashok25 [27]2 years ago

4 0

Answer:

.5/q+4

Step-by-step explanation:

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I just need yall help ... {:

KonstantinChe [14]

Answer:C

Step-by-step explanation:

The answer is C because the minimum is 33 and the maximum is 51. The first quartile is 33. THE SECOND QUATILE IS 39 and the 3rd quartile is 47.

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2 years ago

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PPLEASEE HELP<br> FIND THE VOLUME

Doss [256]

Answer:

volume = 7 * 4 * 24 = 672 m 3

Step-by-step explanation:

a^2 = 25^2 - 7^2 = 576

-> a = 24

volume = 7 * 4 * 24 = 672 m 3

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2 years ago

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a crafter wants to make 20% profit on the items he makes. if the cost of materials is $1.20, what should the items sell for to m

Alborosie

The crafter should sell his crafts for $6

8 0

2 years ago

If f(x) = x^5 - 1, g(x) = 5x, and h(x) = 2x, which expression is

Bad White [126]

The answer is 5(2-9)-1)2

6 0

2 years ago

Consider the following hypothesis test. : : The following results are for two independent samples taken from two populations. Ex

I am Lyosha [343]

Answer:

$z = -1.53$ --- test statistic

$p = 0.1260$ --- p value

Conclusion: Fail to reject the null hypothesis.

Step-by-step explanation:

Given

$n_1 = 80$ $\bar x_1= 104$ $\sigma_1 = 8.4$

$n_2 = 70$ $\bar x_2 = 106$ $\sigma_2 = 7.6$

$H_o: \mu_1 - \mu_2 = 0$ --- Null hypothesis

$H_a: \mu_1 - \mu_2 \ne 0$ ---- Alternate hypothesis

$\alpha = 0.05$

Solving (a): The test statistic

This is calculated as:

$z = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2} }}$

So, we have:

$z = \frac{104 - 106}{\sqrt{\frac{8.4^2}{80} + \frac{7.6^2}{70} }}$

$z = \frac{104 - 106}{\sqrt{\frac{70.56}{80} + \frac{57.76}{70}}}$

$z = \frac{-2}{\sqrt{0.8820 + 0.8251}}$

$z = \frac{-2}{\sqrt{1.7071}}$

$z = \frac{-2}{1.3066}$

$z = -1.53$

Solving (b): The p value

This is calculated as:

$p = 2 * P(Z < z)$

So, we have:

$p = 2 * P(Z < -1.53)$

Look up the z probability in the z score table. So, the expression becomes

$p = 2 * 0.0630$

$p = 0.1260$

Solving (c): With $\alpha = 0.05$ , what is the conclusion based on the p value

We have:

$\alpha = 0.05$

In (b), we have:

$p = 0.1260$

By comparison:

$p > \alpha$

i.e.

$0.1260 > 0.05$

So, we fail to reject the null hypothesis.

4 0

2 years ago